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Drupady [299]
3 years ago
10

Darius deposits $300 into a new savings account. The account earns at a rate of 2.18% every 6 months. How much money does Darius

have at the end of the first 6 months, including the interest he earned? with work please
Mathematics
1 answer:
MAVERICK [17]3 years ago
5 0
45.87= 2.18 plus 300 is 345.87 hope this is correct if not im soooo sorry 
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A full-service salon charges $15.00 for a haircut and $0.45 per hair roller used in a perm. What is the minimum number of hair r
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43 hair rollers.

Step-by-step explanation:

The cost of the haircut ($15.00) and the hair rollers (0.45*43) would equal $34.35, just passing the minimum amount of $34.00.

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Evaluate the limit of lim/n->infinity 6n^2+5/3n^2
castortr0y [4]

we are given

\lim_{n \to \infty} \frac{6n^2+5}{3n^2}

we can see that

degree of numerator = degree of denominator =2

so, we can divide both numerator and denominator by n^2

and we get

\lim_{n \to \infty} \frac{(6n^2+5)/n^2}{(3n^2/n^2)}

\lim_{n \to \infty} \frac{(6n^2/n^2)+(5/n^2)}{(3n^2/n^2)}

now, we can simplify it

\lim_{n \to \infty} \frac{6+(5/n^2)}{3}

now, we can plug n=inf

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=  \frac{6+0}{3}

=  \frac{6}{3}

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(1+sin y)(1+sin (-y))=cos^2 y)
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Who started the problem correctly? The problem form is (-5) - (-1 3/4).
Veronika [31]

Answer:

Shane started the problem correctly

Step-by-step explanation:

We are given problem (-5) - (-1 3/4).

Mariah started the problem as (-5) + 1 - 3/4

Shane started the problem as (-5) + 1 + 3/4

We need to find who started the problem correctly.

The problem should be started by converting the mixed fraction into improper fraction i,e

-5-(-1\frac{3}{4})\\=-5-(-1-\frac{3}{4} )\\=-5-(-\frac{7}{4})

Now we will solve bracket by multiplying -1 with term inside the bracket i.e

=-5+\frac{7}{4}

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Let's compare both the procedures now:

Mariah:

(-5) + 1 - \frac{3}{4}

=(-5) - \frac{1}{4}

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Therefore, Mariah did not start the problem correctly.

Shane:

(-5) + 1 + \frac{3}{4}

= -5 + \frac{7}{4}

= \frac{-13}{4}

Therefore, Shane started the problem correctly.

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