Answer:
150 meters
Step-by-step explanation:
So 1 centimetre is 5 meters, meaning 2 centimetres would be 10 meters.
30 × 1 = 30
30 × 5 = 150
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Answer:
A = $560.00
Step-by-step explanation:
I = A - P = $60.00
Formula:
First, converting R percent to r a decimal
r = R/100 = 6%/100 = 0.06 per year.
Solving our equation:
A = 500(1 + (0.06 × 2)) = 560
A = $560.00
The total amount accrued on a principal of $500.00 at a rate of 6% per year for 2 years is $560.00.
Answer:
The probability of selecting a sample which doesn't capture the true value of μ would be 10% rather than 5% if they decide to calculate a 90% confidence interval rather than a 95% confidence interval from the sample they will select.
Step-by-step explanation:
The correct answer is the last statement, but first, let's look at the other statements:
<em>Their confidence interval would be less likely to capture the </em><em>sample </em><em>mean.</em>
This statement is not correct because the <em>confidence </em>of a confidence interval gives us the probability of capturing the true value of the population mean.
<em>They would </em><em>decrease </em><em>the margin of error of their confidence interval if they calculated a 90% rather than a 95% confidence interval.</em>
If we want more confidence we must establish more precision, which means more error. In other words if the confidence increases so does the error for a fixed sample size. The second statement is false.
<em>The probability of selecting a sample which doesn't capture the true value of μ would be 10% rather than 5% if they decide to calculate a 90% confidence interval rather than a 95% confidence interval from the sample they will select.</em>
As stated before the <em>confidence </em>of a confidence interval is the probability that the interval contains the true value of μ. Therefore, if we increase the confidence from 95% to 90% then this probability also increases. A 90% confidence means that there's a 10% probability of not containing the true mean. Likely, a 95% confidence means that there's a 5% probability of not containig the true mean. The third statement is true.
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