Question

A polynomial p has zeros when x = 5, x = -1, and x = -1/4

Answer 1

Answer:

p(x) =  (x-5) (x+1)(4x+1)

Step-by-step explanation:

We know the equation for a polynomial with zeros is written as

f(x) = a( x-b1) (x-b2)...... where b are the zeros

We have zeros x = 5, x = -1, and x = -1/4

p(x) = a( x-5) (x- -1) (x - -1/4)

p(x) = a (x-5) (x+1) (x+1/4)

Let a = 4

p(x) = 4 (x-5) (x+1) (x+1/4)

p(x) =  (x-5) (x+1)(4x+1)

Answer 2

Answer:

$x=5$  ⇒  $(x-5)=0$

$x=-1$  ⇒$(x+1)=0$

$x=-1/4$ ⇒ $(x+1/4)=0$ ⇒ $(4x+1)=0$

$p(x)=(x-5)(x+1)(4x+1)=0$

$Option(B)$

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Hope it helps...

Have a great day!!