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raketka [301]
3 years ago
13

Labor rate = $7.50 per hour Labor time = 6.5 hours Retail price of parts = $0 Total job cost = $82.00 Overhead rate?

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0
Total cost job=
Retail price of parts+labor cost+manufacturing overhead

Total cost job 82

Retail price of parts 0

Labor cost=7.5×6.5=48.75

Manufacturing overhead ?

82=0+48.75+?

?=82−48.75

?=33.25

Manufacturing overhead is 33.25

Now find manufacturing overhead rate from the cost of labor
33.25÷48.75=0.682×100=68.2%

The answer 68.2%




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A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s
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Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question, we have that:

\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{260 - 270}{21.2}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0
3 years ago
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Firdavs [7]

Answer:

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Step-by-step explanation:

We are provided with the radius of the circle so we can use that to solve for the circumference(perimeter) of the circle. The formula to solve for the circumference is 2*pi*r.

2*pi*7 = 14pi = 43.98 cm

Although this is the circumference of the entire circle... To solve for the circumference of a quarter-circle we must find the quarter of that:

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We are already provided with the other two sides, which are both equal to 7 cm since they are radii.

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8 0
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