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3 years ago

800m or 799,999mm which is greater

Mathematics

2 answers:

erik [133]3 years ago

7 0

800m is the answer, I thought they were both m's

Mariulka [41]3 years ago

4 0

800m is greater than 799,999mm

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(1.3x + 2.4) + (-6.1x – 3.2)

melisa1 [442]

Step-by-step explanation:

In simplify form: 1.3x+2.4-6.1-3.2 = -4.8x-0.8

or factor the expression: =-4/5×(6x+1) Alternate form: -0.8(6x+1). I hope this helps.

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3 years ago

The graph below shows point P and line A. If line B is drawn such that it passes through point P and is parallel to line A, what

n200080 [17]

Answer:

Step-by-step explanation:

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2 years ago

A manufacturer of processing chips knows that 2\%2%2, percent of its chips are defective in some way. Suppose an inspector rando

kipiarov [429]

The data in the question seems a bit erroneous. I am writing the correct question below:

A manufacturer of processing chips knows that 2%, percent of its chips are defective in some way. Suppose an inspector randomly selects 4 chips for an inspection. Assuming the chips are independent, what is the probability that at least one of the selected chips is defective? Lets break this problem up into smaller pieces to understand the strategy behind solving it.

Answer:

The probability that at least one of the selected chips is defective is 0.0776.

Step-by-step explanation:

The question states that the probability of defective chips is 2% i.e. 0.02. Let p denote the probability of selecting a defective chip so, p = 0.02

An inspector selects 4 chips, which means n=4 and we need to compute the probability that at least one of the selected chips is defective. Let X be the number of defective chips selected. We need to compute P(X≥1) which means either 1, 2, 3 or 4 chips can be defective.

We will use the binomial distribution formula to solve this problem. The formula is:

where n = total no. of trials

p = probability of success

x = no. of successful trials

q = probability of failure = 1-p

we have n=4, p=0.02 and q=1-0.02=0.98.

We need to compute P(X≥1) which is equal to:

P(X≥1) = P(X=1) + P(X=2) + P(X=3) + P(X=4)

A shorter method to do this is to use the total probability theorem:

P(X≥1) = 1 - P(X<1)

= 1 - P(X=0)

= 1 - ⁴C₀ (0.02)⁰(0.98)⁴⁻⁰

= 1 - (0.98)⁴

= 1 - 0.9224

P(X≥1) = 0.0776

4 0

4 years ago

First one please thanksssa

serious [3.7K]

In order to find this, we need to count exactly how many times each of them blinks within 60 seconds. Then, we find which numbers are the same.

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60

6, 12, 18, 24, 30, 36, 42, 48, 54, 60

Now, I will bold the numbers that are the same.

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60

6, 12, 18, 24, 30, 36, 42, 48, 54, 60

Now, we have our answer.

Answer: The two neon lights will blink on the 12, 24, 36, 48, and 60 second marks.

Hope I helped!

5 0

3 years ago

Which of the following statements are true? Select all that apply.

tigry1 [53]

Answer:

a,d

Step-by-step explanation:

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3 years ago