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-BARSIC- [3]
4 years ago
11

Abraham has visited 10 countries already. He has a goal of visiting at least 50 countries. He plans to achieve this goal by visi

ting 5 new countries per year (y) for the next several years. Which inequality and solution shows the amount of years that it will take for Abraham to meet his goal?
Mathematics
1 answer:
olasank [31]4 years ago
4 0

Given :

Abraham has visited 10 countries already. He has a goal of visiting at least 50 countries.

He plans to achieve this goal by visiting 5 new countries per year (y) for the next several years.

To Find :

Which inequality and solution shows the amount of years that it will take for Abraham to meet his goal.

Solution :

Let, after x years Abraham visited y countries.

It is mathematically given as :

10 + 5x=y

Now, it is given that his goal is minimum of 50 countries.

So,

10+5x \ge 50\\\\5x\ge 40\\\\x \ge 8

Therefore, minimum years required to meet his goals are 8.

Hence, this is the required solution.

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Step-by-step explanation:

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A lunch bill $12 before tax. If tax on the bill is 7.5%, what is the total cost of the lunch including tax?
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$12.90

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7 0
4 years ago
Read 2 more answers
(-2 1/8) -12 25/29 - 10/7=​
bonufazy [111]

 

\displaystyle\\-2\frac{1}{8}-12\frac{25}{29}-\frac{10}{17}=\\\\\\=-\frac{2\times8+1}{8}-\frac{12\times29+25}{29}-\frac{10}{17}=\\\\\\=-\frac{16+1}{8}-\frac{348+25}{29}-\frac{10}{17}=\\\\\\=-\frac{17}{8}-\frac{373}{29}-\frac{10}{17}=\\\\\\=-\frac{17\times29\times17}{8\times29\times17}-\frac{373\times8\times17}{8\times29\times17}-\frac{10\times8\times29}{8\times29\times17}=\\\\\\=-\frac{8381}{3944}-\frac{50728}{3944}-\frac{2320}{3944}=\\\\\\=\frac{-8381-50728-2320}{3944}=\frac{61429}{3944}

7 0
3 years ago
{8, 15, 9, 18, 9, 17, 22, 10, 11, 9, 13}<br> What is the interquartile range of the data set?
8_murik_8 [283]

Answer:

IQR = 8

Step-by-step explanation:

The interquartile range (IQR) is the difference between the upper quartile Q₃ and the lower quartile Q₁

We require the data arranged in ascending order and to find the median Q₂

The median is the middle value of the data arranged in ascending order.

8, 9, 9, 9, 10, 11, 13, 15, 17, 18, 22

                      ↑ Q₂

The upper quartile is the middle value of the data to the right of the median

13, 15, 17, 18, 22

           ↑ Q₃

The lower quartile is the middle value of the data to the left of the median

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IQR = Q₃ - Q₁ = 17 - 9 = 8

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