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Fofino [41]
3 years ago
9

Tbh im dumb but what are the prime factors of 400 and the square root of 400

Mathematics
2 answers:
Eva8 [605]3 years ago
7 0
The prime factors are:
2 x 2 x 2 x 2 x 5 x 5

The square root is 20
expeople1 [14]3 years ago
3 0
Prime factors: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, and 400.

Square root: √400=√20^2=20
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fiasKO [112]
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6 0
3 years ago
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Solve 5x^2 − 3x + 17 = 9.
Vedmedyk [2.9K]

Answer:

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = \frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}

or

x = \frac{3\pm\sqrt{9-160}}{10}

or

x = \frac{3+\sqrt{-151}}{10} and x = \frac{3-\sqrt{-151}}{10}

or

x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

here i = √(-1)

Hence,

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

7 0
3 years ago
-1/4(4x-8)+18 (distributive property)​
SashulF [63]

Answer:I don’t know

Step-by-step explanation:

:/

3 0
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kirill [66]
7 <= d/-5

hope it helps
8 0
3 years ago
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saw5 [17]

Answer:

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