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3 years ago

Find the HCF and LCM of 20 and 38

Mathematics

2 answers:

Anna007 [38]3 years ago

5 0

I want to help but i remembered im too dumb to know the answer im sorry :((

Vika [28.1K]3 years ago

4 0

Answer:

LCM = 380

HCF = 2

Step-by-step explanation:

Least common multiple (LCM) of 20 and 38 is 380

Greatest common factor (GCF) of 20 and 38 is 2

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Newberg is 8 kilometers due north of the airport, and summer field is 15 kilometers due east of the airport. How far apart are n

Karo-lina-s [1.5K]

Answer:

The correct answer is 17 kilometers.

Step-by-step explanation:

Let A denote the point where the airport is located.

Newberg is located 8 kilometers due north of airport say at point B.

Summer field is located 15 kilometers due east of the airport say at point C.

Thus ABC is the required right angled triangle with sides AB = 8; AC = 15; and ∠A = 90°.

Thus we use Pythagoras theorem to find the value of the side BC which indeed would give us the distance between Newberg and Summer field.

∴ $BC = \sqrt[2]{ AC^{2} + AB^{2} }$ = $\sqrt[2]{ 15 ^{2} + 8^{2}}$ = $\sqrt[2]{289}$ = 17 kilometers.

Thus the distance between Newberg and Summer field is 17 Kilometers.

4 0

4 years ago

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emmasim [6.3K]

This is indeed math yes

7 0

3 years ago

Read 2 more answers

A force of 50 pounds acts on an object at an angle of 45 degrees. A second force of 75 pounds acts on the object at an angle of

Contact [7]

Answer:

The magnitude of the resultant force is:

$R=100.3 \:pound$

The direction is:

$\theta=1.2^{\circ}$

Step-by-step explanation:

Let's find the components of each vector is x and y-directions first.

Sum of x-component vector forces.

$F_{tot-x}=F_{1}cos(45)+F_{2}cos(30)$

$F_{tot-x}=50cos(45)+75cos(30)$

$F_{tot-x}=100.3 \: pound$

Sum of y-component vector forces.

$F_{tot-y}=-F_{1}sin(45)+F_{2}sin(30)$

$F_{tot-y}=-50sin(45)+75sin(30)$

$F_{tot-y}=2.1 \: pound$

The magnitude of the resultant force is:

$R=\sqrt{100.3^{2}+2.1^{2}}$

$R=100.3 \:pound$

The direction is:

$tan(\theta)=\frac{2.1}{100.3}$

$\theta=arctan(\frac{2.1}{100.3})$

$\theta=1.2^{\circ}$

I hope it helps you!

4 0

3 years ago

15 points ! Find m < RQP

Phoenix [80]

Answer:

<RQP = 70°

Step-by-step explanation:

<RQP = 1/2 (140)

<RQP = 70°

4 0

3 years ago

Pls help me

gizmo_the_mogwai [7]

Answer:

yes yes

Step-by-step explanation:

not 100% but it should be right

3 0

3 years ago