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lbvjy [14]
3 years ago
13

Which transformation represents a reflection over the y = x line?

Mathematics
2 answers:
Bond [772]3 years ago
7 0

Answer:

Option c. (x, y) → (y , x)

Step-by-step explanation:

we know that

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places

Remember that each point of a reflected image is the same distance from the line of reflection as the corresponding point of the original figure

so

The rule of the reflection across the line y=x is

(x,y) → (y,x)

Varvara68 [4.7K]3 years ago
7 0

Answer:

c. (x,y)\rightarrow (y,x).

Step-by-step explanation:

We are asked to find the transformation rule that represents a reflection over the y=x line.

We know that when we reflect a point across the line y=x, the x and y coordinates change their place.

The point (x,y) on the image will be (y,x) after a reflection across the line y=x.

Therefore, our required rule would be (x,y)\rightarrow (y,x).

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Andreas93 [3]

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7 0
3 years ago
Simplify the expression ​
finlep [7]

Answer:

\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x} = \frac{x - 6}{4*x}

Step-by-step explanation:

We have the expression:

\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x}

The first thing we want to do, is to have the same denominator in both equations, then we need to multiply the first term by (2/2), so the denominator becomes 4*x

We will get:

(\frac{2}{2} )\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x} = \frac{4*x - 4}{4*x}  - \frac{3*x + 2}{4*x}

Now we can directly add the terms to get:

\frac{4*x - 4}{4*x}  - \frac{3*x + 2}{4*x} = \frac{4*x - 4 - 3*x - 2}{4*x}  = \frac{x - 6}{4*x}

We can't simplify this anymore

3 0
3 years ago
Will 1.11 be more than 1 kilograms?
lutik1710 [3]

Answer:

I have this too idk

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Let R be a relation on the set of all lines in a plane defined by (l 1 , l 2 ) R line l 1 is parallel to l 2 . Show that R is
MArishka [77]

Answer: hello your question is poorly written below is the complete question

Let L be the set of all lines in XY plane and R be the relation in L defined as R = {(L1, L2): L1 is parallel to L2}. Show that R is an equivalence relation. Find the set of all lines related to the line y = 2x + 4.

answer:

a ) R is equivalence

b) y = 2x + C

Step-by-step explanation:

<u>a) Prove that R is an equivalence relation </u>

Every line is seen to be parallel to itself ( i.e. reflexive ) also

L1 is parallel to L2 and L2 is as well parallel to L1 ( i.e. symmetric ) also

If we presume L1 is parallel to L2 and L2 is also parallel to L3 hence we can also conclude that L1 is parallel to L3 as well ( i.e. transitive )

with these conditions we can conclude that ; R is equivalence

<u>b) show the set of all lines related to y = 2x + 4 </u>

The set of all line that is related to y = 2x + 4

y = 2x + C

because parallel lines have the same slopes.

5 0
3 years ago
AB is Tangent to circle O at B. if AB = 7 and AO = 17.4, what is the length of radius r to the nearest tenth?
irakobra [83]
The angle the radius makes with AB is a right angle, so the Pythagorean theorem applies.
  r² = 17.4² - 7² = 253.76
  r = √253.76 ≈ 15.9

The length of radius r is about 15.9.
5 0
3 years ago
Read 2 more answers
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