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Maurinko [17]
3 years ago
6

List the following fractions from least to greatest 1/7 6/7 4/7 3/7

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0

Answer:

1/7, 3/7, 4/7, 6/7

Step-by-step explanation:

There's like denominators(bottom number) so you would list the numerators(top number) from least to greatest.

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volume of a cone = 1/3*(πr²h)

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A certain television is advertised as a 21-inch TV (the diagonal length). If the height of the TV is 13 inches, how wide is the
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The value of the 4th term is 80. the sequence is being doubled each step what is the 7th term?
leva [86]
This is a geometric sequence with common ratio (r) = 2.
an = ar^(n - 1)
a4 = a(2)^(4 - 1) = a(2)^3 = 8a
8a = 80
a = 80/8 = 10

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7. The scale on a map of Florida is 1 ⅛ inches to 25 miles. The distance on the map from Gainesville to Ocala is 1 ⅝ inches. Bas
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8 0
2 years ago
A tank contains 200 liters of fluid in which 50 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
mel-nik [20]

At the start, the tank contains A(0) = 50 g of salt.

Salt flows in at a rate of

(1 g/L) * (5 L/min) = 5 g/min

and flows out at a rate of

(A(t)/200 g/L) * (5 L/min) = A(t)/40 g/min

so that the amount of salt in the tank at time t changes according to

A'(t) = 5 - A(t)/40

Solve the ODE for A(t):

A'(t) + A(t)/40 = 5

e^(t/40) A'(t) + e^(t/40)/40 A(t) = 5e^(t/40)

(e^(t/40) A(t))' = 5e^(t/40)

e^(t/40) A(t) = 200e^(t/40) + C

A(t) = 200 + Ce^(-t/40)

Given that A(0) = 50, we find

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so that the amount of salt in the tank at time t is

A(t) = 200 - 150 e^(-t/40)

7 0
3 years ago
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