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yarga [219]
3 years ago
7

geq%200%20%5C%5C%5C%5C%20-y%5E3-27y%2By%5E2%2B27%2B81%20%5Cgeq%200%20%5C%5C%5C%5C%20-y%5E3%2By%5E2-27y%2B108%20%5Cgeq%200%20%5C%20%5C%20%7C%28-1%29%20%5C%5C%5C%5C%20y%5E3-y%5E2%2B27y-108%20%5Cleq%200" id="TexFormula1" title="81-(y-1)(y^2+27) \geq 0 \\\\ 81-(y^3+27y-y^2-27) \geq 0 \\\\ -y^3-27y+y^2+27+81 \geq 0 \\\\ -y^3+y^2-27y+108 \geq 0 \ \ |(-1) \\\\ y^3-y^2+27y-108 \leq 0" alt="81-(y-1)(y^2+27) \geq 0 \\\\ 81-(y^3+27y-y^2-27) \geq 0 \\\\ -y^3-27y+y^2+27+81 \geq 0 \\\\ -y^3+y^2-27y+108 \geq 0 \ \ |(-1) \\\\ y^3-y^2+27y-108 \leq 0" align="absmiddle" class="latex-formula">
And what should I do from now on? I have to find the solutions for y... Please, a little help here :3
Mathematics
1 answer:
Zarrin [17]3 years ago
7 0
<span>First thing you'll need to know is that the value for this equation is actually an approximation 'and' it is imaginary, so, one method is via brute force method.

You let f(y) equals to that equation, then, find the values for f(y) using values from y=-5 to 5, you just substitute the values in you'll get -393,-296,-225,... till when y=3 is f(y)=-9; y=4 is f(y)=48, so there is a change in </span><span>signs when 'y' went from y=3 to y=4, the answer is between 3 and 4, you can work out a little bit deeper using 3.1, 3.2... You get the point. The value is close to 3.1818...

The other method is using Newton's method, it is similar to this but with a twist because it involves differentiation, so </span>y_{n+1}=y_n-\frac{f(y)}{f'(y)}<span> where 'n' is the number you approximate, like n=0,1,2... etc. f(y) would the equation, and f'(y) is the derivative of f(y), now what you'll need to do is substitute the 'n' values into 'y' to find the approximation.</span>
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Số tiếp theo (next number?): 25 50 99 196 388
Delvig [45]

Answer:

The correct answer is - 768.

Step-by-step explanation:

The given question is based on a specific pattern present in between the numbers in the given series -

Series = 25 50 99 196 388

to find - next number in series

let us find the relation between the initial two number:

25 - 50, here number 50 is two times of 25 or (x*2-0)

relation between 2nd and 3rd number:

50 - 99, here 99 is two times of 50 minus 1 or (x*2-1)

relation between 3rd and 4th number:

99 - 196, here 196 is two times of 99 minus 2 or (x*2-2)

relation between 4th and 5th number:

196 - 388, here 388 is the two times of 196 minus 4 or (x*2-4)

So on this pattern, the next number would be = x*2-8

388*2-8

= 768

5 0
2 years ago
Calculate the mean deviation by median (by using the mid-point(x) of leaf weights. b) A fair die is rolled. Find the probability
SVETLANKA909090 [29]

Answer:

hello attached below is the required table that is missing and the completed table as well

A) mean deviation = 0.1645

B) 2/3

Step-by-step explanation:

From the table we calculated the midpoint value (x) and c.f

N = 27

median class = 2.35 to 2.45

median = l + [ (N/2) - cf / F ] * H

             = 2.35  + [ (13.5 - 13) / 6 ] *0.1 = 2.3583

hence mean deviation by median

= summation of  fi |xi -M| / summation of fi

= 4.4417 / 27 = 0.1645

B ) probability of getting an odd number or prime number or both

the probability of an odd number = 1/2

also the probability of an even number = 1/2

while the probability of getting neither of them = 1/3

hence the probability of getting odd or prime or both

= 1/2 + 1/2 - 1/3 = 2/3

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