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Orlov [11]
3 years ago
5

One section of an auditorium has 12 rows of seats each row has 3 seats what is th total number of seats in tat section

Mathematics
1 answer:
hammer [34]3 years ago
8 0
There are 36 seats in that section
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SOMEONE ANSWER PLEASE PLEASE
Gnom [1K]

Answer:

See explanation below.

Step-by-step explanation:

Let's say,

x = number of tokens required to play one game of ping pong

y = number of token required play one game of pinball

Using the data given, the system of equations are:

\begin{bmatrix}9x+5y=29\\ 3x+y=7\end{bmatrix}

Solving the system of equations using substitution method will give us:

y=4\:\:\:,\:\:\:x=1

So, one game of ping pong required 1 token, whereas one game of pinball required 4 tokens.

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4 years ago
What is -87 = 1 + 8x?​
Leno4ka [110]

Answer:

-87= 1 + 8x

-88= 8x

x= -11

Basically bring over the one to the other side of the equation and solve for x by dividing.

6 0
3 years ago
there are 32 students in ms keys he homeroom. of the students 3/8 are boys. how many boys are in the homeroom
algol13

Answer: 12 out of the 32 would be boys. Hope this helps.

7 0
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Do in five minutes please help me out I will give you points if you help me out thank you
Margaret [11]

Answer:

sorry dude no clue

Step-by-step explanation:

8 0
4 years ago
What should a size of a sample be in order to have a margin of error of 4% for a 90% confidence level from a population with a s
vagabundo [1.1K]

Answer:

We need a sample size of 2,071,800 or higher.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, we find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem:

We need a sample size of n or higher, when M = 0.04, \sigma = 35. So

M = z*\frac{\sigma}{\sqrt{n}}

0.04 = 1.645*\frac{35}{\sqrt{n}}

0.04\sqrt{n} = 1.645*35

0.04\sqrt{n} = 57.575

\sqrt{n} = 1439.375

\sqrt{n}^{2} = (1439.375)^{2}

n = 2,071,800

We need a sample size of 2,071,800 or higher.

6 0
3 years ago
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