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Only do question 8 50 points Topic: Percentage

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Fed [463]2 years ago

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Answer:

...

Step-by-step explanation:

____ [38]2 years ago

3 0

Answer:

see below

Step-by-step explanation:

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$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ Let the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

$\rightarrow$ Now, clearly it is forming a triangle.

So, in triangle ABC,

$\rightarrow$ $\sf{Tan50° \:= \: \frac{BC}{AC}}$

$\rightarrow$ $\sf{1.19 \:= \: \frac{BC}{50}}$

$\rightarrow$ $\sf{1.19 ×50\:= \: BC}$

$\rightarrow$ $\sf{59.5m\:= \: BC}$

$\rightarrow$ Hence, BC = 59.5m

So, BD(total height of the tower) $\sf{ = \:BC+CD}$

$\sf{= \:59.5+1.65}$

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Therefore, total height of the tower = $\sf\purple{ 61.15m.}$

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