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OLEGan [10]
3 years ago
10

The sum of 10and 7 to the difference of a number and 12

Mathematics
1 answer:
anzhelika [568]3 years ago
5 0
( 10 +7) - x = 12 
17 - x = 12
- x = 12 - 17
- x = - 5 
x = 5 

17 - 5 = 12 
You might be interested in
What type of distribution is shown in the frequency table?
BARSIC [14]
It increases then falls, so it is approximately a bell shaped curve.
5 0
4 years ago
What is the measure of an angle if it is 660 less than 6 times its own supplement
otez555 [7]

Answer:

60

Step-by-step explanation:

Since this angle is unknown, let's just represent it with the variable "x". So the supplement angle of "x" is essentially, the value of the angle that we need to add to "x" to get 180. In other words let's just say that the supplement angle is "y". This means that: x+y=180. If we subtract x from both sides we can represent "y" or the supplement angle as: (180-x).

Since it's 660 less than 6 times it's own supplement let's first multiply the supplement by 6

6(180-x) = 1,080-6x

Now let's subtract 660 from it, since it's 660 less

(1,080 - 6x) - (660) = 420 - 6x

This value should be equal to the angle, which is represented as "x". So let's set it equal to x

420-6x=x

Add 6x to both sides

420=7x

Divide both sides by 7

60 = x

8 0
2 years ago
Solve for x . Round to the nearest tenth, if necessary.
Jet001 [13]

Answer:

x = 24.1

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 15 = x/90

90 tan 15 =x

x=24.11542

To the nearest tenth

x = 24.1

7 0
3 years ago
Read 2 more answers
How many triangles exist with the given angle measures? 32°, 51°, 97°
irinina [24]
For each triangle sum of it's angles must add to 180°.
We need to check if these angles satisfy that condition:
32°+51°+97°=180°

They do satisfy. Now we check if any angle has value that is not possible.
32° and 51° angles are OK.
97° angle is also OK. It is obtuse angle.

For each angle measures exactly one triangle exists. In this example we have an obtuse-angle triangle.
6 0
3 years ago
A summer biathalon-style race requires running a certain distance, and then biking a distance 2 miles more than the length of th
Vesnalui [34]

Answer:

The run is 4.875 miles long, while, the bike is 6.875 miles long.

Step-by-step explanation:

Let d = running distance and d' = biking distance.

Given that d' = d + 2 and v = running speed = 6 mph and v' = biking speed = 10 mph.

Since time, t = distance/speed, running time, t = running distance/running speed = d/6 and biking time, t' = biking distance/biking time = d'/10 = (d + 2)/10.

Since the total time, t" = 90 minutes = 1.5 hours,

t + t' = t"

So, d/6 + (d + 2)/10 = 1.5

multiplying through by the L.C.M, 30, we have

30 × d/6 + 30 ×(d + 2)/10 = 30 × 1.5

5d + 3(d + 2) = 45

expanding the brackets, we have

5d + 3d + 6 = 45

collecting like terms, we have

8d = 45 - 6

8d = 39

d = 39/8

d = 4.875 miles

d' = d + 2 = 4.875 + 2 = 6.875 miles

So, the run is 4.875 miles long, while, the bike is 6.875 miles long.

4 0
3 years ago
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