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2 years ago

9

Write a balanced chemical equation for the reaction that occurs when barium carbonate decomposes into barium oxide and carbon di

oxide gas when heated.

1 answer:

n200080 [17]2 years ago

4 0

BaCO3=BaO+CO2
IS THE EQUATION REPLACE = WITH AN ARROW.

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STALIN [3.7K]

Answer: The space occupied by the gas at 400 torr and $25^{o}C$ is 250 mL.

Explanation:

Given: $V_{1}$ = 250 mL, $P_{1}$ = 800 torr, $T_{1} = 50^{o}C$

$V_{2} = ?$ , $P_{2}$ = 400 torr, $T_{2} = 25^{o}C$

Formula used is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{800 torr \times 250 mL}{50^{o}C} = \frac{400 torr \times V_{2}}{25^{o}C}\\V_{2} = 250 mL$

Thus, we can conclude that space occupied by the gas at 400 torr and $25^{o}C$ is 250 mL.

7 0

2 years ago

Help please 20points

lions [1.4K]

Answer:

D

Explanation:

D is the answer because this is the only one having to do with genetics. Fox's genetics changed because it's environment changed.

6 0

2 years ago

Read 2 more answers

How many neutrons are in a Cs-130 isotope?

den301095 [7]

It has 78 neutrons in a cesium

5 0

2 years ago

Calculate the number of O atoms in 0.364 g of CaSO4 · 2H2O

Nikolay [14]

Answer:

<em>= 7.66 x 10²¹ oxygen atoms in 0.364 grams of CaSO₄·2H₂O</em>

Explanation:

For problems like this posting, one needs an understanding of the following topics:

The definition of the mole

<u>1 mole of substance</u> = mass in grams of substance containing 1 Avogadro's Number ( = 6.023 x 10²³ ) of particles of the specified substance. This is generally one formula weight of the substance of interest. From this, the following equivalent relationships should be memorized:

<em> 1 mole = 1 formula weight = 1 mole weight (g)= 6.023 x 10²³ particles</em>

Converting grams to moles:

<em>Given grams => moles = grams/gram formula wt </em>

Converting moles to grams:

<em>Given moles => grams = moles x gram formula wt</em>

_________________________________________________________

<em>Calculate the number of O atoms in 0.364 g of CaSO₄ · 2H₂O.</em>

Given mass CaSO₄ · 2H₂O = 0.364 grams

Formula Wt CaSO₄ · 2H₂O = 172 g/mole

moles CaSO₄ · 2H₂O = mass <em>CaSO4 · 2H2O / formula Wt. CaSO₄ · 2H₂O</em>

<em>= 0.364 g CaSO₄·2H₂O </em><em>/ </em><em>172 g CaSO4·2H2O </em>

<em>= (0.364/172) mole CaSO₄·2H₂O </em>

<em>= 2.12 x 10⁻³ mole CaSO₄·2H₂O </em>

<em>∴ number of Oxy (O) atoms in 0.364 grams CaSO₄·2H₂O </em>

<em>= (2.12 x 10⁻³ mole CaSO₄ · 2H₂O)(6.023 x 10²³ molecules CaSO₄· 2H₂O/ mole)</em>

<em>= 1.276876 x 10²¹molecules CaSO₄· 2H₂O CaSO₄2H₂O </em>

<em>= 1.276876 x 10²¹ molecules CaSO₄· 2H₂O x 6 oxygen atoms / molecule</em>

<em>= 7.661256 x 10²¹ oxygen atoms in 0.364 grams of CaSO₄·2H₂O</em>

<em>= 7.66 x 10²¹ oxygen atoms in 0.364 grams of CaSO₄·2H₂O</em>

<em />

8 0

2 years ago

It requires 334 kJ of heat to melt 1 kg of ice. The largest known iceberg had a volume of about 3.1 x 1013 m³. How much heat was

umka21 [38]

The amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.

<h3>What is the amount of heat required to melt an iceberg that has a volume of about 3.1 x 1013 m³?</h3>

The heat required to melt a unit mass of ice is known as the latent heat of fusion.

The latent heat of fusion of ice of 1 kg= 334 kJ of heat

Mass of iceberg = 3.1 x 10¹³ m³ * 917 kg = 2.8427 * 10¹⁶ kg

Amount of heat required = 2.8427 * 10¹⁶ * 334 = 9.58 * 10¹⁸ kJ.

Therefore, the amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.

Learn more about latent heat of fusion at: brainly.com/question/87248

#SPJ1

8 0

2 years ago