Answer:
Prove: ΔPYJ ≅ ΔPXK
Step-by-step explanation:
Overlapping triangles are said to be triangles that share at least part of a side or an angle.
To prove ΔPYJ is congruent to ΔPXK
First we would draw the diagram obtained from the given information.
Find attached the diagram.
Given:
JP = KP
PX = PY
From the diagram, ΔPYJ and ΔPXK share the line KJ (part of the side of each of the triangle)
KJ ≅ KJ (A reflexive property - the segment is congruent to itself)
In ∆PYJ
JP = KP + KJ
In ∆PXK
KP = JP + KJ
Since JP = KP
KP + KJ = JP + KJ
PJ ≅ PK
The overlapping section makes a smaller triangle KXJ
∠K = ∠J (opposite angles of congruent sides are equal)
In ∆PYJ: PY + YJ + PJ (sum of angles in a triangle)
In ∆PXK: PX + XK + PK (sum of angles in a triangle)
If ΔPYJ ≅ ΔPXK
PY + YJ + PJ = PX + XK + PK
XK ≅ YJ
Therefore, ΔPYJ ≅ ΔPXK
Answer:
radius=2
Step-by-step explanation:
volume= 4/3 pi r^3
32/3pi=4/3r^3
divide out 4/3
8pi=r^3
cube root
r=2
Answer:
D: 7
Step-by-step explanation:
1.75 (7) + 4.50
12.25 + 4.50
= 16.75
16.75 < 20
Answer:
-10/-12
Step-by-step explanation:
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