Answer:
A) probability of failure in next 100 hours given that it has been tested for 500 hours without failure is 0.181
B) probability that exactly two have the metabolic defect is 0.03
Step-by-step explanation:
Part A)
Let X be a exponentially random variable with mean = μ = 500 hrs
For exponential distribution:

λ = 1/μ
λ = 0.002
We have to find the probability of failure in the next 100 hours given that assembly has been tested for 500 hours without a failure.
Using memory less property of exponential distribution:

using

<h3>Part B)</h3>
Chances of occurrence of metabolic defect = 5%
P(C) = .05
No. of randomly selected infants = n =6
We have to find the probability that exactly two have the metabolic defect
⇒x = 2
Using binomial probability density function:
P = ![P=\left[\begin{array}{ccc}n\\x\end{array}\right] p^{x} (1-p) ^{n-x}\\\\=\frac{n!}{x!(n-x)!} p^{x} (1-p) ^{n-x}\\=\frac{6!}{2!4!}(.05)^{2}(.95)^{4}\\= 0.03\\](https://tex.z-dn.net/?f=P%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dn%5C%5Cx%5Cend%7Barray%7D%5Cright%5D%20p%5E%7Bx%7D%20%281-p%29%20%5E%7Bn-x%7D%5C%5C%5C%5C%3D%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D%20p%5E%7Bx%7D%20%281-p%29%20%5E%7Bn-x%7D%5C%5C%3D%5Cfrac%7B6%21%7D%7B2%214%21%7D%28.05%29%5E%7B2%7D%28.95%29%5E%7B4%7D%5C%5C%3D%200.03%5C%5C)
probability that exactly two have the metabolic defect is 0.03
The quotient of <em>n</em> and 12.
Note that n is first, then 12.
B. n/12 is your answer
hope this helps
Answer:
1.) 9.9
2.) 15.6
Step-by-step explanation:
1.) Consider triangle AEH
AEH is a right angle triangle as ∠AEH = 90°
AH is the hypotenuse of the triangle.
Applying Pythagorean theorem

substituting values as given in the question:

∴ EH≈9.9
2.) Consider triangle CDF
CDF is a right angle triangle as ∠CDF = 90°
CF is the hypotenuse of the triangle.
Applying Pythagorean theorem

substituting values as given in the question:

∴ DF≈15.6
I think it is F, but I am a not sure.