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3 years ago

Which expression will produce an answer with the fewest significant figures?

Mathematics

1 answer:

aliina [53]3 years ago

8 0

The answer is: [A]: " 22.4 - 15.1 " .
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A cylinder has a base with a diameter of 10.8 cm and height 15 cm into the volume of a cylinder in a cubic centimeters round you

LekaFEV [45]

Answer:

$V=1,373.44\ cm^3$

Step-by-step explanation:

<u><em>The correct question is</em></u>

A cylinder has a base with a diameter of 10.8 centimeters and height 15 centimeters. Enter the volume of the cylinder, in cubic centimeters. Round your answer to the nearest hundredth

we know that

The volume of a cylinder is equal to

$V=\pi r^{2} h$

where

$r=10.8/2=5.4\ cm$ ----> the radius is half the diameter

$h=15\ cm$

assume

$\pi =3.14$

substitute

$V=(3.14)(5.4)^{2} (15)=1,373.44\ cm^3$

5 0

2 years ago

Please help thanks❗

Fynjy0 [20]

Answer:

U, V

Step-by-step explanation:

4 0

2 years ago

Kara is 4 more than twice as old as Julia. The sum of their ages is 13. How old is Julia?

Thepotemich [5.8K]

Let julia's age be x
Let Kara's age be 4x
x+4x=13
5x=13
x=13/5
2.6 years

3 0

3 years ago

Geometry

Genrish500 [490]

Answer:

Explanation:

3 0

2 years ago

Read 2 more answers

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.

5 0

3 years ago