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3 years ago

3 ratios equivalent to 18:14

1 answer:

8 0

Think of it this way...ratios can be written as fractions...so 18:14 can be written as 18/14...so basically, ur equivalent ratio is just finding equivalent fractions.
18/14 is equivalent to 9/7, 36/28, and 54/42...so 3 equivalent ratios are :
9:7 , 36:28, 54:42.

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You are creating identical coupon booklets to sell for a fundraiser. You have 32 dry cleaning coupons 80 coupons for a local res

marishachu [46]

No. It means that you should find a integer to divide 32 47 80 , and the equals must be integer also. But the 3 numbers have no common factor

3 0

3 years ago

2. BT bisects ZABC. MZABT = 4x-16 and m CBT = 2x + 6 Find MZABT.

Paladinen [302]

Answer:

The measure of angle ABT is 28°

Step-by-step explanation:

* Lets revise the bisector of a angle

- If a ray bisects and angle that mean the ray divide the angle into

two equal parts in measure

- Ex: if the ray BD bisects angle ABC, then the measure of angle ABD is

equal to the measure of angle CBD

* Lets solve the problem

∵ BT bisects ∠ABC

∴ m∠ABT = m∠CBT

∵ m∠ABT = 4x - 16

∵ m∠CBT = 2x + 6

- Equate the two values

∴ 4x - 16 = 2x + 6

- Lets solve the equation by subtracting 2x from both sides and

adding 16 to both sides

∴ 4x - 2x = 6 + 16

∴ 2x = 22 ⇒ divide both sides by 2

∴ x = 11

- Lets find the measure of angle ABT

∵ m∠ABT = 4x - 16

- Substitute x by 11

∴ m∠ABT = 4(11) - 16 = 44 - 16 = 28°

* The measure of angle ABT is 28°

6 0

3 years ago

A function is shown below

Scrat [10]

Answer:

Step-by-step explanation:

Put input value instead of the x into equation and calculate the output:

y = -5x - 7

x = -4, then find the value of y:

y = -5(-4) - 7 = 20 - 7 = 13

The output is 13 when the input is -4

6 0

2 years ago

Read 2 more answers

Two sides of an isosceles triangle are 4 and 8. Which of the following choices could be the measure of the third side?

Feliz [49]

Answer:

8 is answer. isoceles triangles must have two equal sides, where the smaller makes the base and the two larger are the legs.

Step-by-step explanation:

4 0

2 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

Range:

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago