Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
45.864, because 57.33 divided by 100 is 0.5733 that multiplied by 80 is 45.864
Answer:
There are infinite number of triangles that could be achieved with those angles.
To picture this, we only have to imagine a triangle that is either smaller or bigger than the one at hand.
Tracing a series of paralell lines (which guarantee that the angles are being kept), we can draw triangles for infinite values of x,y and z.
Answer:

Step-by-step explanation:
(6, 4)
x = 6 and y = 4
y > -1/2x + 7
Plug in the values to check if it is true.
4 > -1/2(6) + 7
4 > -3 + 7
4 > 4
This statement is false.
(6, 4) lies on the line.
Answer:Negative 34, negative 2 and three-fourths, blank, negative 1.5, 0, 2.3, 10, 25 and one-fifth Which is an integer that can be inserted on the ...
Step-by-step explanation: