Question

Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in Celina's measurement? A: 6.45% B: 7.50% C: 9.12% D: 13.33%

Answer 1

1) 6 - 5.55 = 0.45 feet (the difference between 6 and 5.55)
2) 0.45/6 * 100 = 7.5% (the percentage of error in Celina's measurement)