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makvit [3.9K]
3 years ago
12

Solve for x. -ax+4b>9

Mathematics
2 answers:
sergiy2304 [10]3 years ago
8 0
Let's solve for a.<span><span><span><span>(<span>−a</span>)</span><span>(x)</span></span>+<span>4b</span></span>>9</span>Step 1: Add -4b to both sides.  <span>−ax+4b+−4b</span><span>></span><span>9+−4b</span><span><span>                                                                 −<span>ax</span></span>><span><span>−<span>4b</span></span>+9</span></span>
Step 2: Divide both sides by -x.       <span>−ax−x</span><span>></span><span>−4b+9−x</span><span>                                                                  a<<span><span><span>4b</span>−9</span><span>x</span></span></span>
Fed [463]3 years ago
4 0
-ax+4b>9
-ax>9-4b
-x>(9-4b)/a
x<-(9-4b)/a
x<(4b-9)/a

Answer: x<-(9-4b)/a              or            x<(4b-9)/a
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{2x+7y=-20<br> {x-3y=16<br> Solve for systems of equations
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By solving the linear equations we get the final values of x = 4 & y = 4.

What is the linear equation?

A linear equation is an algebraic equation of the form y=mx + b, where m is the slope and b is the y-intercept, and only a constant and a first-order  term are included.

We have,

               2x + 7y = -20           ----------(i)

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By multiplying equation (ii) with 2 we get,

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by putting value of y in equation (ii) we get,

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1 year ago
What is x in 8 ^ (x - 1 ) = 16 ?<br><br>Please help. ​
Anna007 [38]

Answer:

x=7/3

Step-by-step explanation:

8 ^ (x - 1 ) = 16

We need to rewrite 8 as 2^3  and 16 as 2^4

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We know that a^b^c = a^(b*c)

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The bases are the same so the exponents are the same

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Step-by-step explanation:

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4 years ago
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Expand and simplify (x+9)(x-3)
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Answer:

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= x² -3x+9x-27

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