What is 8x times 9x divided by 2xy???

Mathematics

2 answers:

myrzilka [38]3 years ago

7 0

Answer:

$\frac{36x}{y}$

Step-by-step explanation:

$\frac{8x \times 9x}{2xy} \\ 8 \div 2 \: and \: x \: will \: cancel \: x \: then \: we \: have \\ \frac{4 \times 9x}{y} \\ \frac{36x}{y} |final \: answer \: |$

alex41 [277]3 years ago

6 0

Answer:

Step-by-step explanation:

Hope this helps

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Please help i’m so stuck i can’t do calc for the life of me

KATRIN_1 [288]

Answer:

$-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}$ is the answer. See steps below.

Step-by-step explanation:

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}\\\\-3x^5+11x^4+33x^3-26x^2-36x-6\\\\\mathrm{and\:the\:divisor\:}x^3+6x^2-3x-5:\\\\\mathrm{Quotient}=\frac{-3x^5}{x^3}=-3x^2\\\\\mathrm{Multiply\:}x^3+6x^2-3x-5\mathrm{\:by\:}-3x^2\:\:\rightarrow\:\:-3x^5-18x^4+9x^3+15x^2\\\\\mathrm{Subtract\:}-3x^5-18x^4+9x^3+15x^2\mathrm{\:from\:}-3x^5+11x^4+33x^3-26x^2-36x-6\mathrm{\:to\:get\:new\:remainder}.\\\\\mathrm{Remainder}=29x^4+24x^3-41x^2-36x-6$