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3 years ago

I don’t understand this

Mathematics

1 answer:

mylen [45]3 years ago

7 0

To solve for an unknown number, you have to keep isolating it till it is all alone:
A=P(1+rt)
(1+rt)=A/P
rt=A/P -1
r=(A/P-1)/t

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In the diagram of △△NRQ below, SP∥∥RQ, NS=10, SR=50, and PQ=40. What is the length of NQ?

Delicious77 [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

Can someone solve this?

RoseWind [281]

I can the company sold 3,00 units in 2008, and 5,00 in 2012

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3 years ago

Nikki has 3 pieces of yarn. the first piece is 5/6 feet long the second piece is 5/3 feet long and the third piece is 3/2 oder s

xenn [34]

I think you are asking to sort them according to the shortest to longest in length. For this, it would be helpful to write the fraction into decimal. The equivalent values are as follows:

5/6 = 0.83
5/3 = 1.67
3/2 = 1.50

Therefore, the correct sorting would be as follows:

first yarn
third yarn
second yarn

Hope this answers the question. Have a nice day.

4 0

3 years ago

Solve the system of equations x+y=-8 and -9x-6y=60 by combining the equations

TiliK225 [7]

Answer:

x = - 4 y = - 4

Step-by-step explanation:

x+y= - 8

-9x-6y=60

First, solve for x in the first equation:

x+y = - 8 Subtract y from both sides

x + y - y = -8 - y y cancels on the left

x = - 8 - y

Now plug in what you found for x into the 2nd equation and solve for y.

- 9x - 6y = 60

-9(- 8 - y) - 6y = 60 Multiply out

72 + 9y - 6y = 60

72 + 3y = 60 Subtract 72 from both sides

72 - 72 + 3y = 60 - 72 72 cancels on the left

3y = - 12 Divie both sides by 3

3y/3 = -12/3 3 cancels on the left because 3/3 = 1

y = -4

Now plug your answer for y back into the first equation to get x.

x + y = -8

x + (-4) = - 8 Add 4 to each side

x - 4 + 4 = - 8 + 4 4 cancels on the left

x = -4

x = - 4 and y = - 4

8 0

3 years ago

What is the solution of x=2+ square root x-2?

alex41 [277]

So I'm going to assume that this question is asking for non extraneous solutions, or solutions that are found in the equation and are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

$x-2=\sqrt{x-2}$

Next, square both sides:

$(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2$

Next, subtract x and add 2 to both sides of the equation:

$x^2-5x+6=0$

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

$x^2-2x-3x+6=0$

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

$x(x-2)-3(x-2)=0$

Now you can rewrite the equation as $(x-3)(x-2)=0$

Now, apply the Zero Product Property and solve for x as such:

$x-3=0\\x=3\\\\x-2=0\\x=2$

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

$2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}$

Since both solutions hold true when x = 2 and x = 3, your answer is C. x = 2 or x = 3.

8 0

3 years ago