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Allushta [10]
3 years ago
15

The length and width of a rectangle whose length is 2 centimeters more than the width

Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0

L= 2+w

I cannot solve this, however, because you have not included the total perimeter/area

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Lily visits 100 patients in a month and records the age of each patient. The pie chart below shows the number of patients she ha
iogann1982 [59]

Answer:

15

Step-by-step explanation:

5 0
3 years ago
Brainliest and 50 points
Annette [7]

Answer:

Using the distance formula, when I plugged in the information, the answer I got was the square root of 85. (B)

explanation:

C(x₁ , y₁) and T(x₂ , y₂) OR C(0,4) and T(-6,-3)

CT=√[(x₂ - x₁)² + (y₂ - y₁)²] =√[(-6-0)² + (-3 - 4)²]

CT=√[(36) + (49)} = CT = √85

4 0
3 years ago
Read 2 more answers
PLS HELP ME AM SO STUCK ON THIS
shepuryov [24]

Answer:

it is 612 I think

Step-by-step explanation:

hope this helps

8 0
2 years ago
Which is the graph of f(x) = x2 – 2x + 3?
BaLLatris [955]

Answer:

Step-by-step explanation:

We cannot factor this function out which tells us that there are no zeros. The graph backs this up because we can see that there are none. The easiest way to graph this would start by plugging in points and making a table for yourself.

Lets start by plugging in -1.

(-1)^2-2(-1)+3 =6, this means we have a point at (-1,6).

Now lets plug in 0.

(0)^2-2(0)+3= 3 (0,3)

For plugging in 1

(1)^2-2(1)+3=2 (1,2) (this happens to be the vertex)

And lastly lets plug in 2

(2)^2-2(2)+3=3 (2,3)

Depending on how many points are needed, keep plugging in numbers like we did above.

7 0
3 years ago
Mr Nersin likes to ride his bike. He rode for 1/2 hour. After a short rest, he rode 1/10 hour more. He traveled 4 miles in all.
vodomira [7]
The distance traveled by Mr.Nersin = 4 miles
The time for which Mr.Nersin rode first = 1/2 hour
The time for which Mr.Nersin rode after a short rest = 1/10 hour
Then
The total time for which Mr.Nersin rode = (1/2) + (1/10) hour
                                                                = (5 + 1)/10 hour
                                                                = 6/10 hour
                                                                = 3/5 hour
So
Average speed of Mr. Nersin = Distance traveled / Time taken
                                                = 4/(3/5) miles/hour
                                                = (4 * 5)/3 miles/hour
                                               = 20/3 miles/hour
                                                = 6 2/3 miles/hour
                                                = 6.67 miles per hour
So the average speed at which Mr.Nersin traveled is 6 2/3 or 6.67 miles per hour.
6 0
3 years ago
Read 2 more answers
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