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nadya68 [22]
3 years ago
12

Olve for x. Check each step or answer that is correct. 34(x + 4) = 14(x + 8) (A) Distribute 34 on the left side of the equation.

(B) Distribute 14 on the right side of the equation. (C) Subtract 14x from each side of the equation. (D) Add 3 to each side of the equation. (E) Add 2 to each side of the equation.
Mathematics
1 answer:
Fantom [35]3 years ago
3 0

Answer:

x = -1.2

Step-by-step explanation:

Th given equation is :

34(x + 4) = 14(x + 8)

Step (A) Distribute 34 on the left side of the equation such as :

34x + 34(4) = 14(x + 8)

34x + 136 = 14(x + 8)

Step (B) Distribute 14 on the right side of the equation such as :

34x + 136 = 14x + 14(8)

34x + 136 = 14x + 112

Step (C) Subtract 14x from each side of the equation.

34x + 136 - 14x = 14x + 112 -14x

20x + 136 = 112

Step (D) Subtract 136 from each side of the equation.

20x + 136 -136 = 112 -136

20x = -24

Step (E) Divide both side by 20

\dfrac{20x}{20}=\dfrac{-24}{20}\\\\x=-1.2

So, the value of x is (-1.2). Hence, steps (D) and (E) are incorrect.

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3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval.
anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

f(x)=xe^{-\frac{x^{2}}{32} } , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

              Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

<u>Absolute</u> <u>maximum</u> is a point where the function has its greatest possible value.

<u>Absolute</u> <u>minimum</u> is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

f(x)=xe^{-\frac{x^{2}}{32} }

Using the product rule, first derivative will be:

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} ) = 0

1-\frac{x^{2}}{16}=0

\frac{x^{2}}{16}=1

x^{2}=16

x = ±4

x can't be -4 because it is not in the interval [-2,8].

f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76

f(4)=4e^{-\frac{4^{2}}{32} }=2.42

f(8)=8e^{-\frac{8^{2}}{32} }=1.08

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0
3 years ago
I need the answer to this please.​
ohaa [14]

Answer:

Step-by-step explanation:

Its (1,3) and (-3, -2)

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3 years ago
WILL GIVE BRAINLIEST<br><br> how to to convert numbers from stranded form to scientific notation
kaheart [24]

Hello there!

Soo..to convert a number from standard notation to scientific notation you first have to write a decimal point in the number so that there is only one digit to the left of the decimal point. Sooo for example if u had 240,000 you would put the decimal after the 2 (2.40000)

Hope this helped and have a great day!!


Goodluck (:


7 0
3 years ago
What 2.484848... as a mixed number in simplest form
sergiy2304 [10]

Answer: 2 30303/62500

Hope this helps! :)

Step-by-step explanation:

7 0
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