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Komok [63]

2(x - 2) = -4x + 44

First, expand. / Your problem should look like: $2x - 4 = -4x + 44$
Second, add 4 to both sides. / Your problem should look like: $2x = -4x + 44 + 4$
Third, simplify -4x + 44 + 4 to get -4x + 48. / Your problem should look like: $2x = -4x + 48$
Fourth, add 4x to both sides. / Your problem should look like: $2x + 4x = 48$
Fifth, add 2x + 4x to get 6x. / Your problem should look like: $6x = 48$
Sixth, divide both sides by 6. / Your problem should look like: $x = \frac{48}{6}$
Seventh, simplify $\frac{48}{6}$ to 8. / Your problem should look like: $x = 8$

Answer: x = 8

5 0

2 years ago

Read 2 more answers

Quick question if I had a problem that was sin x = 18.9/20 =.945 how would I inverse sin of both sides ?

Black_prince [1.1K]

Step-by-step explanation:

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8 0

2 years ago

4t- 2=14 what is t<br> Could you please show your work

miskamm [114]

Answer:

your answer is 4 = t

Step-by-step explanation:

add 2 to 14 then divide the 4 to the 16 then you get your answer

6 0

2 years ago

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Math in not my strongest subject!!! Help Please!! 10 points??

Trava [24]

So, okay
$19.500 is 100%
wee need to find 1.5%
so it gonna be 19.500/100=195$ so it is 1%
half of procent will be 97.5
then 1.5% gonna be 195+97.5=292.5
for a year will be 19.792.5$
enjoy it

7 0

3 years ago

Students arrive randomly at the help desk of the computer lab. There is only one service agent, and the time required for inqui

Temka [501]

Answer:

It takes on average 3 minutes to service each student.

Step-by-step explanation:

In queueing problem, an M/M/1 queue model is an arrangement with a single queue, where arrivals at the queue are approximated by a Poisson distribution with mean λ and the service times follows an exponential distribution with mean μ.

The mean number of arrivals in this system is given by:

$\text{Avearge}=\frac{\rho}{1-\rho}$

Here the variable ρ is defined as:

$\rho=\frac{\lambda}{\mu}$

From the average number of arrivals in the system, we can calculate the average number of arrivals in the queue by subtracting the average number of arrivals in service.

That is,

$\text{Average arrivals in queue}=\frac{\rho}{1-\rho}-\rho=\frac{\rho^{2}}{1-\rho}$

The information provided is:

The average number of arrivals of customers is, λ = 12 students/hour.

The average service rate of a single server is, μ = 20 students/hour.

The average of an exponential distribution is:

$E(X)=\frac{1}{\mu}$

Compute the average time it takes to service one student as follows:

$E(X)=\frac{1}{\mu}$

$=\frac{1}{20}\\\\=0.05\ \text{hour}\\\\=3\ \text{minutes}$

Thus, it takes on average 3 minutes to service each student.

4 0

3 years ago