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GrogVix [38]
3 years ago
13

What is the result of dividing the distance around a circle by the distance across the same circle? What number can you use as a

n approximate value for this ratio?
(IM TRYNA FIND THE ANSWER)
Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Answer: The result of the division is the number pi.

And the approximation of pi is: pi = 3.14

Step-by-step explanation:

The distance around a circle is called the perimeter of the circle.

The distance across a circle (This is a line that starts on one point of the circle, go through the center of the circle, and end in the next time it intersects the circle) is called the diameter of the circle.

The quotient between these two quantities is maybe one of the most famous numbers in the world, is the number pi, written as:

π = 3.14159265358979...

Is an irrational number, which means that the decimals keep going infinitely.

Then we can conclude that:

"The result of dividing the perimeter by the diameter, is equal to the number pi = π = 3.14159265358979..."

Because this is an irrational number and is actually impossible to write it, we usually use pi = 3.14 to aproximate it.

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3 years ago
Algebra 2 homework help please!
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How much higher is 8% than 6%
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Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte
Mashcka [7]

Answer:

f'(x) > 0 on (-\infty ,\frac{1}{e}) and f'(x)<0 on(\frac{1}{e},\infty)

Step-by-step explanation:

1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

f'(x)>0

To find its decreasing interval :

f'(x)

2) Then let's find the critical point of this function:

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0

2.2 Solving for x this equation, this will lead us to one critical point since x'  is not defined for Real set, and x''=\frac{1}{e}≈0.37 for e≈2.72

x^{2x}=0 \ni \mathbb{R}\\(ln(x)+1)=0\Rightarrow ln(x)=-1\Rightarrow x=e^{-1}\Rightarrow x\approx 2.72^{-1}x\approx 0.37

3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.

8 0
3 years ago
the amount of food a dog should eat depends on the weight of the dog. 1. identify the independent and dependent variables in thi
fomenos

Here, we are required to identify the dependent and independent variables, the dependency relationship in the situation.

  1. The independent and dependent variables are the weight of the dog and the amount of food it should respectively.
  2. The dependency relationship is thus; The amount of food a dog should eat is a function of the weight of the dog
  3. The dependency relationship using the function notation is; f(x) = {function of x}.

  • The independent variable in this situation is the weight of the dog while the amount of food the dog should eat is the dependent variable. The above is evident from the statement; <em>T</em><em>he amount of food a dog should eat depends on the weight of the </em><em>dog</em><em>.</em>

  • <em>According</em><em> </em><em>to </em><em>the </em><em>premise</em><em> </em><em>given </em><em>in </em><em>the </em>question, it is evident that the dependency relationship is;. The amount of food a dog should eat is a function of the weight of the dog

  • The dependency relationship can be written mathematically using the function notation as;. f(x) = {function of x}.

Read more:

brainly.com/question/11239214

5 0
2 years ago
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