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Naily [24]
3 years ago
8

A store uses the expression –2p + 50 to model the number of backpacks it sells per day, where the price, p, can be anywhere from

$9 to $15. Which price gives the store the maximum amount of revenue, and what is the maximum revenue? (Revenue = price mc023-1.jpg number of backpacks.) $9.00 per backpack gives the maximum revenue; the maximum revenue is $32.00. $12.00 per backpack gives the maximum revenue; the maximum revenue is $312.00. $12.50 per backpack gives the maximum revenue; the maximum revenue is $312.50. $15.00 per backpack gives the maximum revenue; the maximum revenue is $20.00.
Mathematics
2 answers:
Rus_ich [418]3 years ago
8 0
Revenue = price * number of backpacks
number of backpacks = -2p + 50

p = 9 ; -2(9) + 50 = -18 + 50 = 32
revenue = 9 * 32 = 288

p = 12 ; -2(12) + 50 = -24 + 50 = 26
revenue = 12 * 26 = 312

<u>p = 12.50 ; -2(12.50) + 50 = -25 + 50 = 25</u>
<u>revenue = 12.50 * 25 = 312.50</u>   GIVES THE MAXIMUM REVENUE

p = 15 ; -2(15) + 50 = -30 + 50 = 20
revenue = 15 * 20 = 300
lara31 [8.8K]3 years ago
3 0

Answer:

Its C on Edge

Step-by-step explanation:

$12.50 per and maximum of $312.50

Took the Test and got it right.

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A. One player places 1 red, 5 green and 3 blue tiles in Bag A, and 6 red, 4 green, and 2 blue in Bag B. What is the probability
cupoosta [38]

Answer:

\frac{8}{27} is the probability that a player draws out two tiles of the same color assuming they are drawing one tile from each bag.

Step-by-step explanation:

In each bag there are red, green, and blue tiles, meaning that no matter which color is pulled out first there is always some probability that the second tile will be the same color. So, we can set up three possible outcomes:

Red: The player pulls out a red tile first. This has a \frac{1}{9} probability of happening. Then in order to succeed for the problem, the next tile also needs to be red which has a \frac{6}{12} probability attached to it. \frac{1}{9} × \frac{6}{12}=\frac{1}{18} probability of happening.

Green: There is a \frac{5}{9} probability of the player pulling out a green tile first. In this case we want to calculate the probability of the second tile being green, which would be \frac{4}{12}. \frac{5}{9}×\frac{4}{12}=\frac{5}{27}.

Blue: There is a \frac{3}{9} probability of the first tile being blue in which case we are hoping for the second tile to be blue as well. The probability of the second tile being blue is \frac{2}{12} on its own, and them both being blue is  \frac{3}{9}×\frac{2}{12}=\frac{1}{18}

Adding \frac{1}{18}+\frac{1}{18}+\frac{5}{27} we get the answer \frac{8}{27}.

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Please help me please ​
Jlenok [28]
None of them because they are not in order
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