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Naily [24]
3 years ago
8

A store uses the expression –2p + 50 to model the number of backpacks it sells per day, where the price, p, can be anywhere from

$9 to $15. Which price gives the store the maximum amount of revenue, and what is the maximum revenue? (Revenue = price mc023-1.jpg number of backpacks.) $9.00 per backpack gives the maximum revenue; the maximum revenue is $32.00. $12.00 per backpack gives the maximum revenue; the maximum revenue is $312.00. $12.50 per backpack gives the maximum revenue; the maximum revenue is $312.50. $15.00 per backpack gives the maximum revenue; the maximum revenue is $20.00.
Mathematics
2 answers:
Rus_ich [418]3 years ago
8 0
Revenue = price * number of backpacks
number of backpacks = -2p + 50

p = 9 ; -2(9) + 50 = -18 + 50 = 32
revenue = 9 * 32 = 288

p = 12 ; -2(12) + 50 = -24 + 50 = 26
revenue = 12 * 26 = 312

<u>p = 12.50 ; -2(12.50) + 50 = -25 + 50 = 25</u>
<u>revenue = 12.50 * 25 = 312.50</u>   GIVES THE MAXIMUM REVENUE

p = 15 ; -2(15) + 50 = -30 + 50 = 20
revenue = 15 * 20 = 300
lara31 [8.8K]3 years ago
3 0

Answer:

Its C on Edge

Step-by-step explanation:

$12.50 per and maximum of $312.50

Took the Test and got it right.

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Area = 304 cm^2
perimeter = 70
perimeter = 2(l+w)
70 = 2(l+w)
70/2 = l+w
35 = l+w
Now suppose the length would be = x
width would be= 35-x
NOW Area = l*w
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304 = 35x -x^2
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Can someone help me the 2nd problem I don’t understand it
Galina-37 [17]

Answer:

So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.

270 miles

Step-by-step explanation:

So is A is going faster than B so A will reach the destination first.

When will A reach it's destination?

Let's find out.

To solve this problem, the following will come in handy:

Speed=distance/time or time*Speed=distance or time=distance/speed .

time=distance/speed

T_A=\frac{390}{S_A}

T_A=\frac{390}{65}

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So it will take bus A 6 hours to cover the distance of 390 miles.

How much time would have it taken bus B to reach that same distance?

T_B=\frac{390}{45}

T_B=8.\overline{6}

So it would have taken bus B 8.\overline{6} hours to cover a distance of 390 miles.

So the time difference is 8.\overline{6}-6=2.\overline{6} hours.

It will take 2.\overline{6} more hours than bus A for bus B to complete a distance of 390 miles.

So bus B traveled 2.\overline{6} \cdot 45=120 miles (used the time*speed=distance) after bus A got to it's destination.

So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.

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3 years ago
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