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3 years ago

I will give brainliest to the right answer:)

Mathematics

1 answer:

Akimi4 [234]3 years ago

5 0

Answer:

178.1

Step-by-step explanation:

In the first blank, write in 7 for x, and in the second blank, write in 8 for y. Then perform the indicated multiplication and addition.

12.3(7) + 11.5(8), or

86.1 + 92 = 178.1

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Anyone know this I need help

horrorfan [7]

Answer:

option D

Step-by-step explanation:

we have a right triangle

we know

c^2=a^2+b^2

c=hypotenuse

c=52 cm

a=48 cm

b= 20 cm

we substitute in the equation c^2=a^a+b^2

so we have

52^2=48^2+20^2

52= sqrt(48^2+20^2)

52= sqrt(2304+400)

52= sqrt(2704)

52cm=52cm

so c=52 cm

so the option D is the correct answer

7 0

3 years ago

Read 2 more answers

What is 3h^2= h^2 + 18

koban [17]

Answer:

h = ±9

Step-by-step explanation:

3h²= h² + 18 (subtract h²) from both sides

3h² - h²= 18

2h²= 18 (divide both sides by 2)

h² = 18/2

h² = 9

h = ±√18

h = ±9

6 0

3 years ago

There are some Nichols dimes and quarters in a large piggy bank for every two nickels there a sweetheart forever to Diane's ther

maxonik [38]

Question is not proper, Proper question is given below.

There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels, there are 3 dimes. For every 2 dimes, there are 5 quarters. There are 500 coins in all. How many nickels, dimes, and quarters are in the piggy bank? How much are the coins in the piggy bank worth all together?

Answer:

There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.

The piggy bank is worth $91.

Step-by-step explanation:

Let Number of Nickels be represented by 'n'.

Let Number of Dimes be represented by 'd'.

Let of Quarters be represented by 'q'.

Now Given:

For every 2 nickels, there are 3 dimes.

2 n = 3 d

1 n = number of dimes.

We will use Unitary method to find the same.

Number of 1 dimes d = $\frac{3}{2}n$

Also Given:

For every 2 dimes, there are 5 quarters.

2 d = 5 q

1 d = number of quarters

We will use Unitary method to find the same.

Number of 1 quarter q = $\frac{5}{2}d$

Also Given:

Total Number of coins = 500

$n+d+q=500$

Now d = $\frac{3}{2}n$

AND q = $\frac{5}{2}d = \frac{5}{2} \times\frac{3}{2}n = \frac{15}{4}n$

So Substituting the values we get;

$n+\frac{3}{2}n+\frac{15}{4}n=500$

Taking LCM we get making denominator as 4.

$\frac{4}{4}n+\frac{3\times2}{2\times 2}n+\frac{15\times 1}{4\times 1}n=500\\\\\frac{4}{4}n+\frac{6}{4}n+\frac{15}{4}n=500\\\\\frac{4n+6n+15n}{4}=500\\\\\frac{25n}4 =500\\\\25n = 500\times 4\\\\25n =2000\\\\n=\frac{2000}{25}=80$