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kogti [31]
3 years ago
12

PASSAGE: The picnic had been scheduled for weeks in advance. The Morris family was looking forward to some fun and relaxation wi

th friends. Mother Nature, however, didn't feel like cooperating with the family's plans. Dark clouds loomed on the horizon the entire morning. The family met some friends at the entrance to the park. While the kids started playing a game of catch, the adults worried about the possibility of rain. The sky began to darken and rumble as if a storm was about to break. Then, just as suddenly, the clouds parted and the sun shone through. Happy with this turn of events, the adults began setting up the picnic table and chairs.
Which event creates tension in the story?
A) Everyone arrived for the picnic.
B) The sky began to darken and rumble.
C) The sun shines through the clouds.
D) The kids start playing catch.
Computers and Technology
1 answer:
Mekhanik [1.2K]3 years ago
7 0

Answer:

B) The sky began to darken and rumble.

Explanation:

B) The sky began to darken and rumble.

It seems they have arranged it big. Hence, the money is not a problem. Any number of people can be invited,

The problem was certainly that the rain was about to come as sky turned dark and rumble. And hence, this answer as its what created tension.

You might be interested in
In modern computer systems, a byte consists of
Cerrena [4.2K]
8 smaller units, called bits :)
8 0
3 years ago
Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,
Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary                                        denary or decimal

11111111      =        2⁸      =             256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s =  /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11110000.000000                /20

now we have added 4 1s in the 3rd field to reserve 12 0s

<u><em>subnet mask: 255.255.</em></u><u><em>16.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1      </em></u><u><em> 1 </em></u><u><em>      1     1     1     1</em></u>

<u><em>128  64     32    </em></u><u><em>16</em></u><u><em>    8    4     2    1</em></u>

step 3

in the ip network address: 198.16.0.0/19 <em>(subnet representation)</em> we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

          Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts<u><em>+16: 198.16.</em></u><u><em>16</em></u><u><em>.0 - 198.16.31.255</em></u>

<u><em>                   +16: 198.16.</em></u><u><em>32</em></u><u><em>.0- 198.16.47.255 et</em></u>c

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11111000.000000                /21

now we have added 5 1s in the third field to reserve 11 0s

<u><em>subnet mask: 255.255.</em></u><u><em>8.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1       1       </em></u><u><em>1 </em></u><u><em>    1     1     1</em></u>

<u><em>128  64     32    16    </em></u><u><em>8 </em></u><u><em>   4     2    1</em></u>

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (<em>subnet representation</em>) we increment this using 8

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts <u><em>+16: 198.16.</em></u><u><em>24</em></u><u><em>.0- 198.16.31.255</em></u>

<em>                             </em><u><em> +16: 198.16.</em></u><u><em>32</em></u><u><em>.0- 198.16.112.255 et</em></u>c

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11110000.000000                /20

now we have added 4 1s in the 3rd field to reserve 12 0s

<u><em>subnet mask: 255.255.</em></u><u><em>16.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1       1       1     1     1     1</em></u>

<u><em>128  64     32    16    8    4     2    1</em></u>

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts <u><em>+16: 198.16.40.0- 198.16.55.255</em></u>

<em>                          </em><u><em>    +16: 198.16.56.0- 198.16.71.255 et</em></u>c

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11100000.000000                /19

now we have added 3 1s in the 3rd field to reserve 13 0s

<u><em>subnet mask: 255.255.</em></u><u><em>32.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1      </em></u><u><em> 1 </em></u><u><em>      1       1     1     1     1</em></u>

<u><em>128  64     </em></u><u><em>32  </em></u><u><em>  16    8    4     2    1</em></u>

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts <u><em>+16: 198.16.72.0- 198.16.103.255</em></u>

<em>                          </em><u><em>    +16: 198.16.104.0- 198.16.136.255 et</em></u>c

5 0
3 years ago
Assume that a gallon of paint covers about 350 square feet of wall space. Create anapplication with a main() method that prompts
Elena-2011 [213]

Answer:

import java.util.Scanner;

public class PaintClculator {

   public static void main(String[] args) {

Scanner in = new Scanner(System.in);

       System.out.println("Enter Values for length, width, and height of the room");

       double length = in.nextDouble();

       double width = in.nextDouble();

       double height = in.nextDouble();

       double wallArea = calculateWallArea(length,width,height);

       double noGallons = calculatePaint(wallArea);

       double price = price(noGallons);

       System.out.println("Price is: "+ price);

   }

   // Creating Method to Calculate Wall Area

   public static double calculateWallArea( double length, double width, double height){

       // formular for the surface area of a room Area=2*length*heigth+2*width*height+lenth*width

       double Area = 2*length*height+2*width*height+length*width;

       System.out.println("Wall Area: "+Area);

       return Area;

   }

   //Creating method to calculate amount of paint

   public static double calculatePaint(double Area){

       double noGallons = Area/350;

       System.out.println("Number of gallons: "+noGallons);

       return noGallons;

   }

   // Creating Method Calculate Price

   public static double price(double noGallons){

       return noGallons*32;

   }

}

Explanation

  1. Created Three Methods in all; calculateWallArea(), calculatePaint(), and price()
  2. Method calculateWallArea() calculates area based on this formula Area=2*length*heigth+2*width*height+lenth*width
  3. The value of Area is passed to method calculatePaint() Which calculates the number of gallons required to cover the area given that one gallon covers 350 wall space
  4. Method price() calculates and dis[plays the price by calling method calculatePaint() that returns number of gallons. since one gallon is 32$
3 0
3 years ago
How do Brainly experts and verified users format their answers to look like this:
koban [17]

{ \dashrightarrow{ \green{ \tt{use \: the \: latex}}}} \\  \\  { \blue{ \sf{ \: refer \: to \: the \: pdf \: available}}} \\ { \blue{ \sf{at \: https : \  \:  \ \: latex \: on \: brainly}}}

3 0
2 years ago
Read 2 more answers
Think about how you view your emails—either the email service you use yourself or an email service you would choose to use. Desc
Assoli18 [71]

Answer:

and POP3, followed in later years. POP3 is still the current version of the protocol, though this is often shortened to just POP. While POP4 has been proposed, it's been dormant for a long time.

IMAP, or Internet Message Access Protocol, was designed in 1986. Instead of simply retrieving emails, it was created to allow remote access to emails stored on a remote server. The current version is IMAP4, though most interfaces don't include the number.

The primary difference is that POP downloads emails from the server for permanent local storage, while IMAP leaves them on the server while caching (temporarily storing) emails locally. In this way, IMAP is effectively a form of cloud storage.

7 0
2 years ago
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