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kogti [31]
3 years ago
12

PASSAGE: The picnic had been scheduled for weeks in advance. The Morris family was looking forward to some fun and relaxation wi

th friends. Mother Nature, however, didn't feel like cooperating with the family's plans. Dark clouds loomed on the horizon the entire morning. The family met some friends at the entrance to the park. While the kids started playing a game of catch, the adults worried about the possibility of rain. The sky began to darken and rumble as if a storm was about to break. Then, just as suddenly, the clouds parted and the sun shone through. Happy with this turn of events, the adults began setting up the picnic table and chairs.
Which event creates tension in the story?
A) Everyone arrived for the picnic.
B) The sky began to darken and rumble.
C) The sun shines through the clouds.
D) The kids start playing catch.
Computers and Technology
1 answer:
Mekhanik [1.2K]3 years ago
7 0

Answer:

B) The sky began to darken and rumble.

Explanation:

B) The sky began to darken and rumble.

It seems they have arranged it big. Hence, the money is not a problem. Any number of people can be invited,

The problem was certainly that the rain was about to come as sky turned dark and rumble. And hence, this answer as its what created tension.

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The answer is to use the Ctrl and C keys on the keyboard to copy content from one workbook to another.

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What type of lens was used to take this picture?
Leona [35]

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4 0
3 years ago
For this assignment: Analyze and describe the network infrastructure. Describe and explain the various policies that will be nee
mamaluj [8]

Answer:

Explanation:

The Network infrastructure shown here are LAN and WAN. Wired and wireless communications.

The Various policies are:

1. Group related items together, for instance, grouping all Windows servers, into one virtual LAN (VLAN). Other asset groups might include infrastructure (routers, switches, VPNs and VoIP) in one VLAN and security assets (IDS, firewalls, web filters and scanners) may be grouped in another.

2. In general, it is good to adopt a default deny access posture for each VLAN.

3. Network segmentation is a very significant, long-term project, but each step along the way increases security. Log all traffic between segments to determine what is normal and needed for effective functioning.

4. Network segmentation is undeniably and unquestionably an effective component in a defense in depth strategy. Organizations that implement it must be prepared to manage scores of firewalls, switches and routers, each with hundreds of rules, all of which may be affected by the network segmentation process and potentially by updates and changes, even after it is in place.

5. Contribute to a secure WAN environment for all connected departments, offices,

agencies, boards, and commissions

6. Provide a uniform security framework to secure the integrity, confidentiality, and availability of info and info systems, at the WAN level.

7. Provide, in balance with operational requirements, legislative requirements, and information sharing agreements, the minimum WAN security requirements.

8. Raise awareness of information and information technology security needs for all users of the WAN by providing the security principles, requirements.

9. Define the clear roles and responsibilities of all users of the WAN, particularly WAN security staff.

* Vulnerabilities and exposures

1. Data requiring special protection such as credit card numbers that need to comply with PCI-DSS or patient information that is subject to HIPAA should be isolated from other data and put in their own VLANs.

2. Your aim is to limit access to sensitive information to those who need it within the organization and to create roadblocks to stop or slow intruders, who may have broken through one layer of security, from doing further damage.

3. Network segmentation is not a “set and forget” undertaking. The network access policy, defined in firewalls, routers and related devices, changes constantly to cater to new business requirements. Ensure that new changes do not violate your segmentation strategy requires a good degree of visibility and automation.

4. Reducing internal breaches and the infiltration of malicious software(malware). This

internal defense requires significant involvement with individual devices

on a network, which creates greater overhead on network administrators.

*Risks

1. Malicious software, also known as malware,makes its way onto a network through

employees, contractors and visitors. Personal laptops, wireless gadgets,

and of course the USB flash drives, all these provide excellent vectors through which

malware can enter the workplace.

2. Hackers, worms, spammers and other security dangers of the Internet via LAN.

3. The various vulnerabilities on your network represent potential costs — time, money and assets — to your library. These costs, along with the chance someone will exploit these vulnerabilities, help determine the level of risk involved.

4. Since the cost of adding another Internet connection, increasing the speed of the current connection or purchasing complex network monitoring equipment might be too prohibitive, the library has a higher tolerance for a periodically slow Internet connection.

5. External flash drives and other media are also concern when those enters the network.

6. The lost or stolen handheld device poses some serious risks if not incorporated into your network security policy. Such devices are often capable of being formatted of all company content remotely in the case of theft or robbery.

*Security measurements:

1. Address Resolution

Protocol (ARP) spoofing, Denial of Service (DoS) attacks such as Tear Drop

or Ping of Death.

2. In addition, network administrators can form a policy whereby network

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3. Many tools exist to check the existing security state of your network. The Microsoft Baseline Security Analyzer, Nmap .

4. Risk assessment is a combination of both quantifying (the cost of the threat) and qualifying (the odds of the attack).

5. Firewalls.

6. Antivirus systems.

7. Intrusion-detection systems (Host-based IDS,Network-based IDS)

8. Port scanners.

9. Network sniffers.

10. A vulnerability scanner is like a port scanner on steroids.

*Unnecessary Ports

1. It is not easy to say which ports exactly but we should know that the service ports which are open among 65,535 ports and although not exactly sure what service is running , it is safer to check the port and close it as "A Closed Port is a Safe Port".

7 0
3 years ago
In python:
Misha Larkins [42]

Answer:

Following are the code to this question:

list_val = input()#defining a integer variable for input value

test_grades = list(map(int, list_val.split()))#defining test_grades as a list

sum_extra = -999 #defining sum_extra that holds negative integer value

sum_extra = 0#defining sum_extra that holds value

for y in range(len(test_grades)):#defining a for loop to check range of list  

   if(test_grades[y] > 100):# defining if block that check list value is greater then 100

       sum_extra = sum_extra + (test_grades[y] - 100)#use sum_extra variable to hold extra value and add this value

print('Sum extra:', sum_extra)#print value

Output:

101 83 107 90

Sum extra: 8

Explanation:

In the above code a, "list_val" variable is declared, that uses an input method to input the values and declared a "test_grades" variable that uses a list method to add all values in the list.

In the next step, the "sum_extra" variable is declared, which holds some values and defines a for loop to check the range of the "test_grades", and define a if block, that checks list value is greater than 100. If the condition is true, it will remove the extra value, and add it into the sum_extera variable and add its value, and at the last use, print variable to print its value.

6 0
3 years ago
CO! Oher...9
kondor19780726 [428]

Answer:

Altitude of the town(h1) = 1,196.8 m

Explanation:

Given:

Height of barometer(h) = 65 cm Hg = 0.65

Standard atmospheric pressure  = 76 cm Hg = 0.76

Density of mercury(Pm) = 13,600 kg/m³

Density of  air (Pa) = 1.25 kg/m³

Find:

Altitude of the town(h1)

Computation:

Pressure due column = Δp mercury column

(Pa)(h1) = (Pm)(h)

(1.25)(h1) = (13,600)(0.76-0.65)

(1.25)(h1) = 1,496

Altitude of the town(h1) = 1,196.8 m

6 0
3 years ago
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