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notka56 [123]
4 years ago
12

QUESTION 9 of 10: Bob charged $200 for a plane ticket last month. When he received his statement, he saw that he could pay the m

inimum balance of just $25. Bob calculated it would take just 8 months to finish paying off his $200 ticket. Is he correct?
Computers and Technology
2 answers:
den301095 [7]4 years ago
4 0

Answer:

yes he is correct it will take him 8 months to finish paying of the $200 charged on his plane ticket.

Explanation:

total cost of ticket = $200

minimum payment on ticket = $25

If Bob was charged $200 ad he could pay a minimum of $25 then

to pay back a $200 plane ticket with a minimum of $25 it will take:

total cost of ticket / minimum payment on ticket which is:

$200 / $25 = 8 months

IgorLugansk [536]4 years ago
3 0

Answer:

yes cuz 25x8=200

Explanation:

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Formulas is the BEST answer to your question.

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3 years ago
Use the variables k, d, and s so that they can read three different values from standard input--an integer, a double, and a stri
Nat2105 [25]

Answer:

The c++ program to implement the given scenario is shown below.

#include <iostream>

using namespace std;

int main() {

   // variables declared as mentioned

   int k;

   double d;

   string s;

   cout << " Enter an integer value, a double value, a string value in the mentioned order " << endl;

   cin >> k >> d >> s;

   // variables printed in reverse order

   cout << " Reverse order " << endl;

   cout << s << " " << d << " " << k << endl;

   // variables printed in original order

   cout << " Original order " << endl;

   cout << k << " " << d << " " << s << endl;

   return 0;

}

OUTPUT

Enter an integer value, a double value, a string value in the mentioned order  

12 45.67 brainly

Reverse order  

brainly 45.67 12

Original order  

12 45.67 brainly

Explanation:

1. All the variables are declared as mentioned in the question.

int k;

   double d;

   string s;

2. The user is prompted to enter values for integer, double and string variables respectively. The input is accepted in the order mentioned above.

cin >> k >> d >> s;

3. The input is accepted in a single line since this is mentioned in the scenario that variables should be printed in the order in which they are read.

4. These variables are displayed to the standard output in reverse order – string, double, integer. The variables are displayed with exactly one space in between them.

cout << s << " " << d << " " << k << endl;

5. Then, variables are displayed in the original order – integer, double, string. The variables are displayed with exactly one space in between them.

cout << k << " " << d << " " << s << endl;

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3 years ago
Which of the following is a domestic business activity?
harkovskaia [24]
What are the options?

7 0
3 years ago
Read 2 more answers
In JAVA please:
blagie [28]

Answer:

import java.util.Scanner;

public class ArraysKeyValue {

public static void main (String [] args) {

final int SIZE_LIST = 4;

int[] keysList = new int[SIZE_LIST];

int[] itemsList = new int[SIZE_LIST];

int i;

keysList[0] = 13;

keysList[1] = 47;

keysList[2] = 71;

keysList[3] = 59;

itemsList[0] = 12;

itemsList[1] = 36;

itemsList[2] = 72;

itemsList[3] = 54;  

/* Your solution goes here */

for ( i = 0; i < SIZE_LIST; i++){

 if (keysList[i]>50){

  System.out.println(itemsList[i] + " ");  }  }

System.out.println("");

}

}

Explanation:

I will explain the whole program flow.

  • There are two arrays here
  • keysList and itemsList
  • The first list (keysList) contains the following elements:

13 element at first position of the array (0th index)

47 element at second  position of the array (1st index)

71 element at third position of the array (2nd index)

59 element at fourth position of the array (3rd index)

  • The other list (itemsList) contains the following elements:

12 element at first position of the array (0th index)

36 element at second  position of the array (1st index)

72 element at third position of the array (2nd index)

54 element at fourth position of the array (3rd index)

  • The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.
  • Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
  • So the program control enters the body of the loop.
  • In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.
  • In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
  • So the output of the above program is:

72

54

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3 years ago
Jeremy knows that there is a keyboard shortcut in Word, but he does not know what it is. What should Jeremy do to find out what
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The correct answer to this question is that Jeremy should use the F1 key.

In Word, the F1 key is the help button that will help Jeremy find any keyboard shortcut that he is looking for. After pressing F1, he can search for what he is looking for. A second option to find a keyboard short would be to perform a simple search on the Internet for what he is looking for.

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