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3 years ago

How do I solve y=5x-1 and y=15x-1

Mathematics

2 answers:

lakkis [162]3 years ago

7 0

$5x-1=15x-1\Rightarrow x=0\Rightarrow y=-1$

bija089 [108]3 years ago

6 0

$\left \{ {{y=5x-1} \atop {y=15x-1}} \right. \\ \\ (5x-1)=15x-1 \\ (5x-1)+1=(15x-1)+1 \\ 5x=15x \\ (5x)-5x=(15x)-5x \\ 0=10x \\ \frac{0}{10} = \frac{10x}{10x} \\ 0=x \\ \\ y=5(0)-1 \\ y=0-1 \\ y=-1 \\ \\ solution:(0,-1)$

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2 years ago

Encuentra la ecuacion de la parabola con vertice en el origen y foco en las cordenadas 0,1en su forma ordinaria y general

marusya05 [52]

Answer:

$x^{2}=4y$

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Step-by-step explanation:

Forma ordinaria

La ecuación de la parabola de manera ordinaria está dada por:

$(x-h)^{2}=4p(y-k)$ (1)

Donde:

(h,k) es la coordenda del vértice, en nuestro caso (0,0) ya que está en el origen.
(h,k+p) es la coordenda del foco, en nuestro caso (0,1).

Por lo tanto h = 0, k = 0 y p = 1.

Remplazando estos valores en la ecuación de la parábola, tenemos:

$(x-0)^{2}=4*1(y-0)$

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Forma general

La forma general de una parábola esta dada por la siquiente ecuación

$y=ax^{2}+bx+c$

Reordenando la ecuación (2) tenemos:

$y=\frac{1}{4}x^{2}$

Espero esto te haya ayudado!

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3 years ago

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Make them both equal to y

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These are perpendicular since ones slope is -2 and the other is the opposite, 1/2.

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3 years ago

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S_A_V [24]

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3 years ago

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