Answer:
what are the equations to the math on this?
There are infinite many planes that contain each line and point
<h3>How to determine the number of planes?</h3>
The given parameters are given as:
- Line KL and G
- Line JI and G
As a general rule, a line and a point can be used to draw as many planes as possible
This means that there are infinite many planes possible
Hence, there are infinite many planes that contain each line and point
Read more about planes and points at:
brainly.com/question/14366932
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Answer:
2X-3Y = -1
Step-by-step explanation:
given equation is 3X +2Y = -7
FIRST BRING THIS IN SLOPE INTERCEPT FORM
2Y = -3X -7
DIVIDING EACH TERM BY 2
Y = (-3/2)X -7/2
SLOPE OF GIVEN EQUATION IS -3/2
SLOPE OF LINE PERPENDICULAR TO THIS IS NEGATIVE RECIPROCAL HENCE SLOPE OF REQUIRED EQUATION IS 2/3
EQUATION OF STRAIGHT LINE IN POINT SLOPE FORM IS
Y-Y1 = m(X-X1)
Y-1 = (2/3)(X-1)
MULTIPLYING ALL TERMS BY 3
3(Y-1) = 2(X-1)
3Y-3 = 2X -2
2X-2 = 3Y-3
2X-3Y =-3+2
2X-3Y = -1
Answer:
38
Step-by-step explanation:
f(x)=6x+2
6x6 (6 sqaured)
f(36)=36x+2
Now we add 36+2
38
Lets say x is the smaller number and y is the bigger number.
x + y = 436
x + 134 = y
We can substitute the second equation into the first (substitute x + 134 in for y)
x + (x+134) = 436
2x + 134 = 436
2x = 302
x = 151
We can now plug this back into either formula (i use the second)
151 + 134 = b
b = 285
The 2 numbers are 151 and 285
