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3 years ago

Solve 3(x - 2) < 18.

Mathematics

2 answers:

DiKsa [7]3 years ago

8 0

Answer:

simple , isn't it? try to learn

Crazy boy [7]3 years ago

4 0

Answer:

$3(x - 2) < 18 \\ = 3x - 6 = - 6x < 18$

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Tara and Ashley spent the same amount at the grocery store. Tara bought 5 pounds of apples. Ashley bought 3 pounds of apples and

alexandr402 [8]

Answer:

one pound of apple cost $2.5

Step-by-step explanation:

Let the amount they both spent at the grocery store be y and x be the price of apples per pound.

Since Tara bought 5 pounds of apples, 5x = y (1) and Ashley bought 3 pounds of apples and $5 worth other groceries, 3x + 5 = y (2).

Equating both expressions, 5x = 3x + 5

collecting like terms,

5x - 3x = 5

2x = 5

dividing both sides by 2, we have

x = 5/2

x = 2.5

So one pound of apple cost $2.5

7 0

3 years ago

Please help me ASAP Please help

m_a_m_a [10]

Answer:

5 X 4

Step-by-step explanation:

If you plot the dots, youll obviously see a rectangle. The height of the rect. is 4, while the length is 5, so the measurements would be 5 x 4.

Hope this helped!!

6 0

3 years ago

Evan invested $800 in an account that pays 3.25% interest compounded annually.

Aleksandr [31]

Answer:

Evans would have $852.8

Step-by-step explanation:

Given

$PV = \$800$

$r = 3.25\%$

$t = 2$

$n = 1$ --- annually'

Required

The future value

This is calculated using:

$FV = PV*(1 + \frac{r}{n})^{nt$

So, we have:

$FV = 800 * (1 + 3.25\%/1)^{2*1}$

$FV = 800 * (1 + 3.25\%)^{2}$

$FV = 800 * (1 + 0.0325)^{2}$

$FV = 800 * (1 .0325)^2$

$FV = 852.845$

$FV = 852.8$

FV =

8 0

3 years ago

What is the exact circumference of a circle with a diameter 15 inches

stepan [7]

47. 12388980384689 would be the exact circumference of a circle witha diameter of 15 inches :)

3 0

3 years ago

What is the area of a 45 degree sector of a circle with a radius of 12 in.

Elodia [21]

given ,

a circle of radius 12 inches

and $\theta$ = 45°

now we know that ,

$\\{Area \: of \: sector = \frac{\theta}{360\degree} \times \pi \: r {}^{2} } \\ \\$

let's now plug in the values of radius and theta as 12 inches and 45° respectively ,

$\\\dashrightarrow \: \frac{45}{360} \times \frac{22}{7} \times 12 \times 12 \\ \\ \dashrightarrow \: \frac{1}{8} \times \frac{22 \times 12 \times 12}{7} \\ \\ \dashrightarrow \: \frac{22 \times 12 \times 12}{56} \\ \\ \dashrightarrow \: \frac{3168}{56} \\ \\ \dashrightarrow \: 56.57 \: inches {}^{2} (approx.)$

hope helpful :D

6 0

2 years ago