Answer:
6=72 cm; 7=15 cm; 8=30 in; 9)56.5 degrees; 10)40 in
Step-by-step explanation:
6) The height of the triangle is 12 cm. The base is around 10 cm. Triangles are 1/2(b)h, so:
1/2(10)=5
5*12=60 cm
72 is closest to this.
7) Volume is l*w*h, so:
2.5*1.5=3.75
3.75*4=15 cm
8) Again, the height is 5 and the base is 12. 1/2(b)h means:
1/2(12)=6
6*5=30 in
9) All triangles have 180 degrees. So first, add the degrees you know:
33.5+90=123.5
Now, subtract that from 180:
180-123.5=56.5
10) Trapezoids can be found by multiplying the height by the smaller base, so:
6*8=40 in
Hope this helped!
The monthly amortization is P23,511.63
<h2>Compound interest</h2>
The formula for calculating the compound interest is expressed as:
![A = P(1+r/n)^t](https://tex.z-dn.net/?f=A%20%3D%20P%281%2Br%2Fn%29%5Et)
whrere:
- P is the principal = P700,000
- r is the rate = 12% = 0.12
- t is the time = 4 years
- n = 12
Substitute the parameters
![A = 700000(1+0.12/12)^{4(12)}\\ A = 700,000(1.01)^{48}\\ A =1,128,558.25](https://tex.z-dn.net/?f=A%20%3D%20700000%281%2B0.12%2F12%29%5E%7B4%2812%29%7D%5C%5C%0AA%20%3D%20700%2C000%281.01%29%5E%7B48%7D%5C%5C%0AA%20%3D1%2C128%2C558.25)
Calculate the monthly payment:
Monthly payment = ![\frac{1,128,558.25}{48} =23,511.63](https://tex.z-dn.net/?f=%5Cfrac%7B1%2C128%2C558.25%7D%7B48%7D%20%3D23%2C511.63)
Hence the monthly amortization is P23,511.63
Learn more on compound interest here: brainly.com/question/24924853
Answer:
f(-14) = -6
f(-4) = 6
f(12) = 6
f(0) = -3
negative
Step-by-step explanation:
f(-14) = -6
This is because when x is -14, y is -6, as seen in the graph
f(-4) = 6
This is because when x is -4, y is 6, as seen in the graph
f(12) = 6
This is because when x is 12, y is 6, as seen in the graph
f(0) = -3
This is because when x is 0, y is -3, as seen in the graph
is f(4) positive or negative?
negative
This is because when x is 4, y is -6, as seen in the graph
This equation is not factor-able, so we can use the quadratic formula.
x=(-11+square root(11^2-4(-12*-3)))/(2*-12)
x=(-11+square root(-23))/(-24)
Since we have the square root of a negative in this equation, there are no real roots for the quadratic.
Use these equations when converting polar equations to parametric equations:
![x=r\cos\theta](https://tex.z-dn.net/?f=x%3Dr%5Ccos%5Ctheta)
![y=r\sin\theta](https://tex.z-dn.net/?f=y%3Dr%5Csin%5Ctheta)
We know that
, so substitute that into both equations for x and y.
![x=5\theta\cos\theta](https://tex.z-dn.net/?f=x%3D5%5Ctheta%5Ccos%5Ctheta)
![y=5\theta\sin\theta](https://tex.z-dn.net/?f=y%3D5%5Ctheta%5Csin%5Ctheta)
Now, replace
with any variable that you want to represent the parametric equations in. I'll use the standard variable, ![t](https://tex.z-dn.net/?f=t)
![x=5t\cos t](https://tex.z-dn.net/?f=x%3D5t%5Ccos%20t)
![y=5t\sin t](https://tex.z-dn.net/?f=y%3D5t%5Csin%20t)
Thus,
represented in parametric form is:
![(x,y)=(5t\cos t, 5t \sin t)](https://tex.z-dn.net/?f=%28x%2Cy%29%3D%285t%5Ccos%20t%2C%205t%20%5Csin%20t%29)
Let me know if you need any clarifications, thanks!
~ Padoru