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3 years ago

Larry has at least 3 more books than Pat. If Pat has 6 books, what do you know about the number of books Larry has?

Mathematics

1 answer:

ryzh [129]3 years ago

7 0

Answer:

Larry has at least 9 books

Step-by-step explanation:

just add 6 and 3 to get 9. and since it says at least 3 more, you would know that even after adding them, he would have at least 9.

That was a bad explanation, but I hope you know what I mean, if you dont, just comment on my answer and ask any questions about it :)

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a store makes a profit of $8 on a sweater after a markup of 40%. what is the selling price of the sweater?

gulaghasi [49]

If you would like to know what is the selling price of the sweater, you can calculate this using the following steps:

40% of x is $8
40% * x = 8
40/100 * x = 8 /*100/40
x = 8 * 100 / 40
x = $20

Result: The selling price of the sweater is $20.

4 0

3 years ago

Read 2 more answers

What is the math answer

never [62]

Answer:

Step-by-step explanation:

The perpendicular diameter to the chord divides it into two congruent parts.

Since

VU⊥XS,
XT=3b-1,
TS=b+5,

we have that XT=TS.

Hence,

3b-1=b+5,

3b-b=5+1,

2b=6,

b=3.

So,

XT=3·3-1=9-1=8

TS=3+5=8

and

XS=XT+TS=8+8=16.

7 0

3 years ago

Read 2 more answers

Alex is designing a triangular shaped park the park includes tennis courts ball fields and playground equipment located at the v

kondaur [170]

Answer:

centroid

Step-by-step explanation:

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=5%5Cfrac%7B1%7D%7B4%7D%20%20%2B%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%20%2B%201%20%20%5Cfrac%7B5%7D

kobusy [5.1K]

Answer:

7 5/12

Step-by-step explanation:

5 1/4 + 3/4 + 1 5/12

We can add the first two terms

5 1/4 + 3/4

5 4/4

6 + 1 5/12

7 5/12

4 0

3 years ago

The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand

Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean strength of 50 items = 74.28

$\sigma$ = population standard deviation = 2.15

n = sample of items = 50

$\mu$ = population mean tensile strength after machine was adjusted

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $74.28-1.96 \times {\frac{2.15}{\sqrt{50} } }$ , $74.28+1.96 \times {\frac{2.15}{\sqrt{50} } }$ ]

= [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.

8 0

3 years ago