The answer is 2 because you have to divide these numbers.<span />
<span>Assume
p=735 Torr
V= 7.6L
R=62.4
T= 295
PV-nRT
(735 Torr)(7.60L)= n (62.4Torr-Litres/mole-K)(295K)
0.30346 moles of NH3
Find moles
0.300L solution of 0.300 M HCL = 0.120 moles of HCL
0.30346 moles of NH3 reacts with 0.120 moles of HCL producing 0.120 moles of NH4+ ION, and leaving 0.18346 mole sof NH3 behind
Find molarity
0.120 moles of NH4+/0.300L = 0.400 M NH4+
0.18346 moles of NH3/0.300L = 0.6115 M NH3
NH4OH --> NH4 & OH-
Kb = [NH4+][OH]/[NH4OH]
1.8 e-5=[0.300][OH-]/[0.6115]
[OH-]=1.6e-5
pOH= 4.79
PH=9.21
.</span>
<u>Answer:</u> The correct answer is temperature of the gas.
<u>Explanation:</u>
Average kinetic energy of the particles is defined as the average of the kinetic energies of all the particles in a gas molecule. The equation used to calculate the average kinetic energy of a gas is given by:
![K=\frac{3}{2}\frac{RT}{N_A}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B3%7D%7B2%7D%5Cfrac%7BRT%7D%7BN_A%7D)
where,
K = kinetic energy of the gas
R = gas constant
T = temperature of the gas
= Avogadro's number
From the above equation, kinetic energy is directly related to the temperature of the gas molecule. As, the temperature of the gas increases, kinetic energy also increases and vice-versa.
![\text{Kinetic energy}\propto \text{Temperature}](https://tex.z-dn.net/?f=%5Ctext%7BKinetic%20energy%7D%5Cpropto%20%5Ctext%7BTemperature%7D)
Hence, the correct answer is temperature of the gas.
Answer:
24.5 g of NaCl
Explanation:
We begin from the balanced reaction:
3MgCl₂ + 2Na₃PO₄ → 6NaCl + Mg₃(PO₄)₂
If the sodium phosphate is in excess, then the limting reagent is the magnessium chloride.
We convert mass to moles:
20 g . 1mol / 95.2g = 0.210 moles.
3 moles of MgCl₂ can produce 6 moles of NaCl
0.210 moles of salt, may produce (0.210 . 6) /3 = 0.420 moles
Ratio of reactant is twice the product
We convert the moles to mass:
0.420 mol . 58.45 g/mol = 24.5 g