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maxonik [38]
3 years ago
11

For which values of x is the inequality 3(1 + x) > x + 17 true? A) 2 & 3 B) 4 & 5 Eliminate C) 6 & 7 D) 8 & 9

Mathematics
2 answers:
scZoUnD [109]3 years ago
5 0
3(1 + x) > x + 17

a.
3(1 + 2) > 2 + 17  
3 × 3 > 2 + 17
9 > 19         this has no solution so eliminate this.

b.
3(1 + 4) > 4 + 17
3 × 5 > 4 + 17
15 > 21        no solution.

c.
3(1 + 6) > 6 + 17
3 × 7 > 6 + 17
21 > 23       no solution.

d.
3(1 + 8) > 8 + 17
3 × 9 > 8 + 17
27 > 25        this is a solution.

so your answer is d.

hope this helps, God bless!
Scorpion4ik [409]3 years ago
3 0

Answer:

well it  is D make sure you put her brainlyest XD

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skad [1K]

Answer:

$27.00

Step-by-step explanation:

We first have to start at the base value of $45.00, as without that, we have nothing to go off of. We can work right to left because we start at the rightmost point of the problem.

Therefore, we start with finding 9/10 of 45.00 . This is as simple as multiplying 9/10 with 45.00, resulting in 40.5

To figure out a percentage relative to real numbers, we first have to turn that percentage into a fraction or decimal. To turn it into a decimal, we simply divide by 100, and 66 2/3 divided by 100 is roughly 0.6666 , or 2/3 . Multiplying our result of 40.5 by this, we get $27.00 as our answer.

3 0
3 years ago
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Temka [501]

Answer:

Shaded area = 6^2 * ( pi/3 - sqrt(3)/2 )

= 6.52 square units (to 2 places of decimals)

Step-by-step explanation:

see solution by same author given in

brainly.com/question/17023327?answeringSource=feedPersonal%2FhomePage%2F2

(question 17023327)

Please refer to the diagram for additional letters and measures.

Let

r=radius (OA and PA) of each circle

Area of sector PAOB

= (60+60)/360 * pi * r^2

=pi*(r^2)/3

Area of triangle PAB

= 2* (r cos(60) * r sin(60) /2)

= 2* ((r/2) * r (sqrt(3)/2) /2)

= sqrt(3) * r^2 / 4

= r^2 * sqrt(3)/4

Area of segment AOB

= area of segment PAOB - area of triangle PAB

= r^2 * ( pi/3 - sqrt(3)/4 )

By symmetry, area of shaded area

= area of segment AOB  -  area of triangle AOB

= area of segment AOB  -  area of triangle PAB

= r^2 * ( pi/3 - sqrt(3)/4 )  -   r^2 * ( sqrt(3)/4)

= r^2 * ( pi/3 - 2*sqrt(3)/4 )

= r^2 * ( pi/3 - sqrt(3)/2 )

Since r = b, we substitute

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= b^2 * ( pi/3 - sqrt(3)/2 )

Substitute b=6

area

= 6^2 * ( pi/3 - sqrt(3)/2 )

= 6.522197 square units

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3 years ago
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Answer:

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jeka57 [31]

The answer is:   "  y − 1  =  - 3(x + 2) " .
__________________________________________________________

Explanations: 
__________________________________________________________

<u>Note</u>:  The "point-slope form" of the equation of a line is:

                  →     " y − y₁ = m(x −x₁) " . 

We are given the slope,  m" , is:  " - 3 " ;  

We are given a point on the line [on the graph that is represented by this equation];  with the coordinates:  " (-2 , 1) " ;  

                          →   which is in the format: " (x₁ , y₁) " ;
                                      
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_____________________________________________________
As aforementioned, the equation of a line in "point-slope form" ;  is:  
_________________________________________________________
                          →    " y − y₁ = m(x − x₁) " ;  

in which:
 
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 →   " m "  =   the slope of the line [represented by the equation] " ; 

We proceed by substituting our known values for "m" ;  "y₁" ; and "x₁" :
 
 →       " y − 1  =  - 3(x − (-2) ) "  ;   
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 →   Rewrite as:
_______________________________________________________
 →      "  y − 1  =  - 3(x + 2) "  ;  

 →    which is our answer;  since it is written in "point-slope form" .
_______________________________________________________
3 0
3 years ago
The top 1/8 of the runners advance to the fi nals for the track and field competit ion. What is the decimal value of the number?
Ivan

Answer:

no

Step-by-step explanation:


8 0
3 years ago
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