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olasank [31]
3 years ago
7

Rate of change between (2,11) and (8,14)

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0

Answer:

1/2

Step-by-step explanation:

the rate of change is = the change in y/ the change in x

if the points are (2, 11) and (8, 14)  

Rate of change = (14-11) / (8-2) = 3 / 6 = 1/2

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In 2011, a firm books the following:  increase in cash, $0; increase in inventories $13; increase in accounts receivable, $29; i
zmey [24]
<span>given: increase in inventories= $13 increase in accounts receivable =$29 increase in accounts payable=$17 solution: change in net working capital = increase in inventories + increase in accounts receivable - increase in accounts payable. change in net working capital = 13+29-17 = $25</span>
6 0
3 years ago
Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then
tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}

Compute the number of candies in the sixth jar as follows:

\text{Number of candies in the 6th jar}=\frac{63}{32}x\\

                                                    =\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42

Thus, the number of candies in the sixth jar is 42.

4 0
3 years ago
Hey here some points free but add me as a friend bc ya know
jek_recluse [69]

Answer:

added!

Step-by-step explanation:

6 0
3 years ago
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GalinKa [24]
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5 0
3 years ago
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The sum of two numbers is twenty-four. The difference of the two numbers is four.
RSB [31]

Answer:

x + y = 24

x - y = 4

Now, add these two equations.

You get,

2x = 28

x =  \frac{28}{2}

x = 14

Given,

x + y = 24

14 + y = 24

y = 24 - 14

y = 10

You can test this to the other equation as well.

x - y = 4

14 - 10 = 4

Hence, the two numbers are 14 and 10.

3 0
3 years ago
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