Value of Trig functions questions

Mathematics

1 answer:

77julia77 [94]3 years ago

4 0

In the given quadrant, sine and cosine are negative and tangent is positive.

cos(θ) = -√(1 - (-5/8)²) = (-√39)/8

tan(θ) = sin(θ)/cos(θ) = 5/√39 = (5√39)/39

csc(θ) = 1/sin(θ) = -8/5

sec(θ) = 1/cos(θ) = -8/√39 = (-8√39)/39

cot(θ) = 1/tan(θ) = (√39)/5

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Step-by-step explanation:

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The domain asks for all the included x values. It goes from the lowest x value to the highest x value. Our lowest x value is -4 and the function stops at an x value of 4. So the domain is

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The range goes from the lowest y value to the highest y value. Our lowest y value is -2 and the highest y value is 4. So the range is

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That straight line that comes after the first x and y is the line that translates to "such that". In words, our domain reads "x such that x is greater than or equal to -4 and less than or equal to 4" and the range reads "y such that y is greater than or equal to -2 and less than or equal to 4".

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