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Natali [406]
3 years ago
9

Anyone know how do do this?​

Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0

Answer:

Step-by-step explanation:

A relation is a function if there are no shared x values.  If you look at the y-axis where x = 0, you can see that there are 2 coordinates that share that x value:

(0, -1) and (0, 3).  Because the x value in both those coordinates is the exact same number, this is NOT a function, merely a relation.  ALL functions are relations, but not all relations are functions.

The domain asks for all the included x values.  It goes from the lowest x value to the highest x value.  Our lowest x value is -4 and the function stops at an x value of 4.  So the domain is

D = {x | -4 ≤ x ≤ 4}

The range goes from the lowest y value to the highest y value.  Our lowest y value is -2 and the highest y value is 4.  So the range is

R = { y | -2 ≤ y ≤ 4}

That straight line that comes after the first x and y is the line that translates to "such that".  In words, our domain reads "x such that x is greater than or equal to -4 and less than or equal to 4" and the range reads "y such that y is greater than or equal to -2 and less than or equal to 4".

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Help please! I need this ASAP Find the value of x
sasho [114]

Answer:

The value of x is 30°

Step-by-step explanation:

We are given that the outer angle of the parallelogram is 60 degrees. Therefore it's respective inner angle will be 180 - 60 = 120 degrees. And, by properties of a parallelogram, the angle opposite to this angle will be 120 degrees as well.

If we draw extend the line creating angle 2x, then we will make ( 1 ) a vertical angle to 2x, ( 2 ) a 90 degree angle, and ( 3 ) and angle that we can let be y. Therefore, 2x + y = 90, and 3x + y = 120.

\begin{bmatrix}2x+y=90\\ 3x+y=120\end{bmatrix} ,

\begin{bmatrix}6x+3y=270\\ 6x+2y=240\end{bmatrix} ,

6x+2y=240\\-\\\underline{6x+3y=270}\\y=30,  

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Solution : x = 30°

4 0
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