In a large population, 61% of the people are vaccinated, meaning there are 39% who are not. The problem asks for the probability that out of the 4 randomly selected people, at least one of them has been vaccinated. Therefore, we need to add all the possibilities that there could be one, two, three or four randomly selected persons who were vaccinated.
For only one person, we use P(1), same reasoning should hold for other subscripts.
P(1) = (61/100)(39/100)(39/100)(39/100) = 0.03618459
P(2) = (61/100)(61/100)(39/100)(39/100) = 0.05659641
P(3) = (61/100)(61/100)(61/100)(39/100) = 0.08852259
P(4) = (61/100)(61/100)(61/100)(61/100) = 0.13845841
Adding these probabilities, we have 0.319761. Therefore the probability of at least one person has been vaccinated out of 4 persons randomly selected is 0.32 or 32%, rounded off to the nearest hundredths.
You did not give a full question! sorry
Answer: 1 8/9
Step-by-step explanation: you convert 1 1/3 to 1 3/9 then add 5/9 to 1 3/9 to get a total of 1 8/9
N
8
→
I used
n
as the unknown number
Explanation:
The quotient is the result of division between two numbers.
The quotient of a number (I used
n
) and
8
would be
n
8
247.5 is the answer I hope this will help u bye and god blesses u!
