Answer:
Selling price of watch A and watch B= Rs. 425
Let cost price of watch A=x
Profit =10%
∴
100
110
x=425
x=386.36
Let cost price of watch B=y
Loss =10%
∴
100
90
y=425
y=472.22
Net cost price =x+y=858.5858
Net selling price =850
Loss%=
858.58
858.5858−850
×100=1%
Explanation:
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Answer:
1.93
Explanation:
Moles of C
H
COOH = 38/1000 × 0.50 = 0.019mol
Moles of CHCOONa = Mass/Molar mass = 2.64/144.10 = 0.018321mol
Final pH = pKa + log([CHCOONa]/[CHCOOH]
= -log Ka + log(mols of CHCOONa]/mols of CHCOOH
= -log(6.5 × 10^(-5)) + log (0.018321/0.019)=4.17
change in pH = final - initial pH
= 4.17 - 2.24
=1.93
Molality is defined as the number of moles of solute in 1 kg of solvent.
molality of solution to be prepared is 0.50 molal
this means that in 1000 g of water there should be 0.50 mol of NaCl
if 1000 g of water should contain - 0.50 mol
then 750.0 g of water requires - 0.50 mol/kg x 0.750 kg = 0.375 mol
mass of NaCl in 0.375 mol - 58.5 g/mol x 0.375 mol = 21.9 g
therefore a mass of 21.9 g of NaCl is required
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