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Tanzania [10]
3 years ago
5

You do an experiment in which you need 0.25 mole of tyrosine (C,H11 NO3).

Chemistry
1 answer:
Marina CMI [18]3 years ago
6 0

Answer:

B.90.5 g

Explanation:

not 100%sure hehe

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2 years ago
What is the value for AG at 5000 K if AH = -220 kJ/mol and S= -0.05 kJ/(mol-K)?
Serhud [2]

Answer:

C. 30 kJ

Explanation:

Hello there!

In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

\Delta G= \Delta H-T\Delta S

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

\Delta G=-220kJ/mol-5000K*-0.05kJ/mol*K\\\\\Delta G=30kJ/mol

Therefore, the answer is C. 30 kJ .

Best regards!

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