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3 years ago

On a scale drawing, the scale is 1 inch = 1 foot. Find the scale factor.

Mathematics

2 answers:

ankoles [38]3 years ago

6 0

It would be 1/12 that would be the answer to that.

balu736 [363]3 years ago

3 0

The answer is 1:12 or 1/12

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A school district is considering moving the start of the school day at Groveland High from 8:00 a.m. to 9:00 a.m. to allow stude

DaniilM [7]

Answer:

The answer is " $\bold{(7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} }\\\\$ "

Step-by-step explanation:

Given values:

$\bar{x_1}=7.1\\\\\bar{x_2}=8.3\\\\s_1=1.7\\\\s_2=1.9\\\\n_1=50\\\\n_2=39$

Using formula:

$\to (\bar{x_1} -\bar{x_2}) \pm t \sqrt{\frac{(s_1)^2}{n_1}+\frac{(s_1)^2}{n_2}} \\\\$

Put the values in the above formula:

$\to (7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} \\\\$

4 0

3 years ago

PLZ HELP

Mekhanik [1.2K]

Sounds like you’re dealing with absolute value.

1. Cookies
2. Bananas
3. Bananas and ice cream are the closest

4 0

2 years ago

GIVING BRAINLIEST AND 20 points!

mestny [16]

Answer:

The answer is 27

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2(3y+6+3)=196−16

(2)(3y)+(2)(6)+(2)(3)=196+−16(Distribute)

6y+12+6=196+−16

(6y)+(12+6)=(196+−16)(Combine Like Terms)

6y+18=180

Step 2: Subtract 18 from both sides.

6y+18−18=180−18

6y=162

Step 3: Divide both sides by 6.

162

y=27

3 0

2 years ago

. Toby invested £4500 for 2 years in a savings account. He was paid 4% per annum COMPOUND

Anton [14]

Answer:

£4867.2

Step-by-step explanation:

Given data

P= £4500

T=2 years

R= 4%

The compound interest expression

A=P(1+r)^t

substitute

A= 4500(1+0.04)^2

A=4500(1.04)^2

A=4500*1.0816

A=£4867.2

Hence the balance is £4867.2

4 0

2 years ago

The population mean annual salary for environmental compliance specialists is about $62,000. A random sample of 32 specialists

lakkis [162]

Answer: 0.002718

Step-by-step explanation:

Given : The population mean annual salary for environmental compliance specialists is about $62,000.

i.e. $\mu=62000$

Sample size : n= 32

$\sigma=6200$

Let x be the random variable that represents the annual salary for environmental compliance specialists.

Using formula $z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$ , the z-value corresponds to x= 59000 will be :

$z=\dfrac{59000-62000}{\dfrac{6200}{\sqrt{32}}}\approx\dfrac{-3000}{\dfrac{6200}{5.6568}}=-2.73716129032\approx-2.78$

Now, by using the standard normal z-table , the probability that the mean salary of the sample is less than $59,000 :-

$P(z$

Hence, the probability that the mean salary of the sample is less than $59,000= 0.002718

3 0

3 years ago