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GarryVolchara [31]
3 years ago
12

Solve by factoring x3 + 8x2 + 5x − 14 = 0.

Mathematics
2 answers:
QveST [7]3 years ago
5 0
Is it x^3+8x^2+5x-14?
stiv31 [10]3 years ago
5 0
X3+16+5x-14=0
8x+2=0
8x=-2
x= -2/8
x= -.25
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I realy need help please​
hjlf

Answer:

x = 128 degrees

Step-by-step explanation:

First figure out the angle inside the triangle

1st step: add 55 and 73 together:

⇒ 55 + 73 = 128

2nd step: subtract the sum from 180:

⇒ 180 - 128 = 52

to find x, take 180 again and then subtract 52 from it:

⇒ 180 - 52 = 128

5 0
2 years ago
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3(-2a-4)+3a what would this be i have so many questions today to ask y'all
Novay_Z [31]

Answer:

<h2>- 3(a + 4)</h2>

Solution,

3( - 2a - 4) + 3a \\  = 3 \times ( - 2a) - 3 \times 4 + 3a \\  =  - 6a - 12 + 3a \\  =  - 6a + 3a - 12 \\  =  - 3a - 12 \\  =  - 3(a + 4)

Hope this helps...

Good luck on your assignment...

8 0
3 years ago
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How did changes to the voting process affect voter participation?
Jobisdone [24]

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A) more people voted

Step-by-step explanation:

I did it on edge

4 0
3 years ago
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Give an example of how you use positive and negative numbers, and explain the meaning of 0 in your example.
EastWind [94]

Answer:

Meanings of the numbers:

Most numbers represent an amount. Positive numbers represent above zero. Zero is the only number that does not represent an amount. It means nothing. When you go lower than nothing, you are in the negative numbers. Negative numbers represent absent values pretty much.

How I would use them in every day life:

I would use positive numbers to represent... maybe something I'm trying to get at a store. Ex: 4 bananas

I would use negative numbers to... maybe look at the temperature. Ex: -16 degrees Fahrenheit. Negative numbers are in temperature all the time.

Hope this helps! (^-^)

6 0
2 years ago
Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred
Ksivusya [100]

1. m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}, then m\angle ABC=m\angle ACD and triangles ADC and ACB are similar by AAA theorem.


2. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{AC}{AB}= \dfrac{AD}{AC}.


3. Knowing lengths you could state that \dfrac{b}{c}= \dfrac{e}{b}.


4. This ratio is equivalent to b^2=ce.


5. m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}, then m\angle BAC=m\angle BCD and triangles BDC and BCA are similar by AAA theorem.


6. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{BC}{BD}= \dfrac{AB}{BC}.


7. Knowing lengths you could state that \dfrac{a}{d}= \dfrac{c}{a}.


8. This ratio is equivalent to a^2=cd.


9. Now add results of parts 4 and 8:


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10. c is common factor, then:


b^2+a^2=c(e+d).


11. Since e+d=c you have a^2+b^2=c\cdot c=c^2.



7 0
3 years ago
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