Since it says m1 is 120 and it says find m3 don’t you need to multiply or I’m wrong
Answer:
0.2941 = 29.41% probability that it was manufactured during the first shift.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Defective
Event B: Manufactured during the first shift.
Probability of a defective item:
1% of 50%(first shift)
2% of 30%(second shift)
3% of 20%(third shift).
So

Probability of a defective item being produced on the first shift:
1% of 50%. So

What is the probability that it was manufactured during the first shift?

0.2941 = 29.41% probability that it was manufactured during the first shift.
Answer:
B -1/5
you have to follow pemdas first get rid of the parethase which leaves you with 2+3x+6x=-4x+8x+1 then you add what you can do then you get 2+9x=4x+1 then you subtract 2 from both sides and subtract 4x from both sides which leaves you with 5x=-1 then you divide 5 from both sides and get x=-1/5
The answer is .5. That is the answer because .5/10 = .05.