Answer:
600 minutes
Step-by-step explanation:
If we write both situations as an equation, we get:
y1 = 24 + 0.15x
<em>y1 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>paid </em><em>in </em><em>first </em><em>plan</em>
<em>x </em><em>:</em><em> </em><em>total minutes </em><em>of </em><em>calls</em>
y2 = 0.19x
<em>y2 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>in </em><em>second </em><em>plan</em>
<em>x:</em><em> </em><em>total </em><em>min</em><em>utes </em><em>of </em><em>call</em>
We are now looking for the situation where the total cost in the two plans is equal, so
y1 = y2
this gives
24 + 0.15x = 0.19x
<=> 0.04x = 24
<=> x = 600
Answer:
The product of two numbers is the result you get when you multiply them together. So 12 is the product of 3 and 4, 0 is the product of 4 and 5 and so on.
Step-by-step explanation:
Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.
Answer:
1.9x10^-2
hope this helps
Step-by-step explanation:
1:4
2:8
3:12
4:16
5:20 then just graph it according to the x and y coordinates
