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leonid [27]
3 years ago
13

What is the y intercept of the line passing through the point (5,-6) with the slope of -1/7

Mathematics
1 answer:
Agata [3.3K]3 years ago
6 0

Answer:

The equation of the line would be y = -1/7x - 37/7

Step-by-step explanation:

In order to find this, we need to start with point-slope form.

y - y1 = m(x - x1)

Now we can input the slope in for m and the point in for (x1, y1)

y + 6 = -1/7(x - 5)

y + 6 = -1/7x + 5/7

y = -1/7x - 37/7

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Is line p || to line q? Why?
bonufazy [111]

Step-by-step explanation:

yes, because the angles match. per rule of intersecting lines the angles in one side of an intersected line are the same but mirrored on the other side of the line.

since q behave exactly as p would regarding the intersecting angles, they are parallel.

6 0
3 years ago
Find the missing exponent. 10 =1,000
Hoochie [10]

Answer:

10^3

Step-by-step explanation:

An easy way to get exponents done if you're dealing with a multiple of 10, is to count the number of 0's present.

Since there are 3 0's in 1000, 10*10*10 = 1000 which just so happens to be the exponent needed

5 0
2 years ago
What is the slope-intercept form of the equation of the line parallel to the line in the graph that passes through the point (-1
Sedbober [7]

Answer:

undefined

Step-by-step explanation:

4 0
3 years ago
What number adds to 25 but multiples to get 50
aleksandrvk [35]
Times two 25×2=50 thats the answer
3 0
3 years ago
Write an equation for the nth term of the given geometric sequence<br> -12,-36,-108...an
julsineya [31]

Answer:

nth term of the geometric sequence

an= -12*3^(n-1)

Step-by-step explanation:

First term

a= -12

Second term

ar= -36

-12r=-36

r=-36/-12

=3

Third term

ar^2= -108

-12(3)^2

= -12(9)

= -108

nth term of the geometric sequence

an=ar^(n-1)

= -12*3^(n-1)

7 0
3 years ago
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