In the graph, if the number of manufactured units falls below 6.25, then the business will be operating in what state?

Mathematics

1 answer:

AURORKA [14]3 years ago

6 0

It would be in a state of loss because the units manufactured neither reaches nor exceeds the break even point.

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Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ

marissa [1.9K]

Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2

5 0

3 years ago

Which expression uses the associative property to make it easier to evalute?

mixas84 [53]

Answer:

The correct option is (c).

Step-by-step explanation:

The given expression is :

$14(\dfrac{3}{2}\times \dfrac{1}{4})$

We need to use the associative property to make it easier.

The associative property for multiplication is as follows :

$A\times (B\times C)=(A\times B)\times C$

We have,

$A=14, B=\dfrac{3}{2}\ and\ C=\dfrac{1}{4}$

$14(\dfrac{3}{2}\times \dfrac{1}{4})=(14\times \dfrac{3}{2})\times \dfrac{1}{4}$

Hence, the correct option is (c).

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2 years ago

A team has 3 wins for every loss they loss games how many did they win??

OLEGan [10]

The team has lost only 6 games (according to the comments). Let's say "x" is the amount of losses and "y" is the amount of wins.

For every loss, they have 3 wins, so in the end, this would be the equation:
$y = 3x$
or
$y = 3 \times x$
Although the first one would be the easier and most understandable to read.

So:
y = 3(6)
would equal
18

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Answer:

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